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3 years ago

ANSWER FAST PLZ!!!!!!!!!

Chemistry

2 answers:

valina [46]3 years ago

7 0

I think the answer is B

Vikentia [17]3 years ago

6 0

the answer is gonna be b

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What is the molarity of the solution formed by mixing 0.20mol of sodium hydroxide with enough water to make 150 ml of solution?

bixtya [17]

Molarity is defined as the number of moles of solute in 1 L of solution
number of NaOH moles present - 0.20 mol
volume of solution - 150 mL
since molarity is taken as number moles of solute in 1000 mL
if 150 mL contains - 0.20 mol
then 1000 mL should contain - 0.20 / 150 x 1000 = 1.33 mol
therefore molarity is 1.33 M

3 0

3 years ago

how many moles of an ideal gas would occupy a 25.0 liter container when the temperature is 295 K and the pressure is 0.850 atm?

BlackZzzverrR [31]

Answer:

Required number of moles of ideal gas is 0.877 moles.

Explanation:

Pressure (P) = 0.850 atm

Temperature (T) = 295 K

Volume (V) = 25 ltr

Universal gas constant (R) = 0.0821

no of moles (n) = ?

we have the ideal gas equation as:

PV= nRT

or, 0.850× 25 = n × 0.0821 × 295

or, n = 0.877 moles

Hence the required number of moles of an ideal gas is 0.877 moles.

8 0

3 years ago

A155-g sample of a unknown substance was heated from 25.0°C to 40.0°C.In the process, the substance absorbed 5696 J of energy. W

Iteru [2.4K]

The answer is: (5696 J) / (155 g) / (40.0 - 25.0)°C = 2.45 J/g·°C

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3 years ago

Explain how chemists overcome the problem of low yield In industry

mrs_skeptik [129]

High temperature and pressure produce the highest rate of reaction. However, this must be balanced with the high cost of the energy needed to maintain these conditions. Catalysts increase the rate of reaction without affecting the yield. This can help create processes which work well even at lower temperatures.

I hope this helps you.

8 0

3 years ago

6. Cuando se oxidan en el aire 12,120 g de vapor de Zinc se obtienen 15,084 g del óxido. ¿Cuál es la fórmula empírica del óxido?

Eddi Din [679]

Answer:

12120 g + O2 = 15084 g

m Zn = 12.120 Kg

m óxido = 15.084 Kg

1. calcular la masa de cinc en gramos

g = 12,120 Kg x 1000 = 12120 g de cinc

g = 15.084 Kg x 100 = 15084 g de oxígeno

2. calcular gramos de Oxigeno

g O = 15084 g - 12120 g = 2964 g O2

3. calcular % de Zn y O

%m/m ( m soluto / m solc.) x 100

%m/m (Zn) = ( 1210 g / 15084 g ) x 100

% m/m (Zn) = 80.35 % = 80.35 g

%m/m (O) = ( 2964 g / 15084 g ) x 100

% m/m (Zn) = 19.65 % = 19.65 g

4. Calcular moles de cada elemento

Zn: 80.35 g / 65.38 g/mol = 1.228 mol

O: 19.65 g / 16 g/mol = 1.228 mol

5. dividir entre el menor de los elementos

Zn: 1.228 mol / 1.228 mol = 1

O: 1.228 mol / 1.228 mol = 1

6. Fórmula empírica: ZnO

3 0

3 years ago