Answer:
True. An English scientist by the name of John Newlands tried to classify the elements in a unique manner. He first started by arranging all the elements in a ascending order according to their atomic weights.
what is the question ? I don't see any question but a few words
Answer: They are typically smaller than spiral galaxies.
Some show evidence for prior collision or close encounter with another galaxy.
They exhibit vigorous star-forming activity.
Irregular galaxies are typically smaller than spiral or normal ellipticals, of irregular form, and without spiral arms. Irr I galaxies are often characterized by lots of gas, dust, and associated star formation. Irr II galaxies have forms that indicate prior collisions or close encounters with other galaxies. Irregular galaxies are one of the most common types of galaxies.
Answer:
The surface-to-volume ratio of a C-60 fullerene is 3:77.
Explanation:
Surface area of sphere = 
Volume of the sphere = 
where : r = radius of the sphere
Radius of the C-60 fullerene sphere = r = 77 pm
Surface area of the C-60 fullerene = 
...[1]
Volume area of the C-60 fullerene = 
..[2]
Dividing [1] by [2]:
The surface-to-volume ratio of a C-60 fullerene is 3:77.
The combustion of an organic compound is mostly written as,
CaHbOc + O2 --> CO2 + H2O
where a, b, and c are supposed to be the subscripts of the elements C, H, and O in the compound. Determining the number of moles of C and H in the product which is the same as that in the compound,
(Carbon, C) : (561 mg) x (12/44) = 153 mg x (1 mmole/12 mg) = 12.75
(Hydrogen, H) : (306 mg) x (2/18) = 34 mg x (1 mmole/1 mg) = 34
Calculating for amount of O in the sample,
(oxygen, O) = 255 - 153 mg - 34 mg = 68 mg x (1mmole/16 mg) = 4.25
The empirical formula is therefore,
C(51/4)H34O17/4
C3H8O1
The molar mass of the empirical formula is 60. Therefore, the molecular formula of the compound is,
C9H24O3
