The statement which is true about <em>Atom A</em> and <em>Atom B</em> is; Choice B: <em>Atom B will give up electrons to form bonds.</em>
According to the question;
For Atom A:
- the electron configuration is; <em>1s²2s²2p³</em>
- Therefore, it has 5 valence electrons.
For atom B:
- the electron configuration is; <em>1s²2s²2p⁶3s²3p¹</em>
- Therefore, it has 3 valence electrons.
Since, electrons need 8 electrons to assume a full octet;
Consequently, Atom B will give up electrons to become stable.
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Hence the answer is C
Answer:
44.91% of Oxygen in Iron (III) hydroxide
Explanation:
To solve this question we must find the molar mass of Fe(OH)3 and the molar mass of the oxygen in this molecule. Percent composition will be:
<em>Molar mass Oxygen / molar mass Fe(OH)3 * 100</em>
<em />
<em>Molar mass Fe(OH)3 and oxygen:</em>
1Fe = 55.845g/mol*1 = 55.845
3O = 16.00g/mol*3 = 48.00 - Molar mass of Oxygen
3H = 1.008g/mol*3 = 3.024
55.845 + 48.00 + 3.024 =
106.869g/mol is molar mass of Fe(OH)3
% Composition of oxygen is:
48.00g/mol / 106.869g/mol * 100 =
<h3>44.91% of Oxygen in Iron (III) hydroxide</h3>
I believe it is b. I hope this helps you
If two different elements combine separately with a fixed mass of a third element, the ratio of the masses in which they do so are either the same as or a simple multiple of the ratio of the masses in which they combine with each other.
