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sveticcg [70]
3 years ago
10

4. Define power and explain how to determine power.

Chemistry
1 answer:
Ratling [72]3 years ago
5 0
The rate of doing work is called power of an object.
It is also defined as the work done by an object per unit time. Mathematically, its formula is given by :
, W is work done and t is time taken.
The SI unit of power is watts and its commercial unit is kWh.
1 watt = J/s or N-m/s.
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A 40.0 L balloon is filled with air at sea level (1 atm @ 25 oC). It is then tied to a rock and thrown into a cold lake and it s
velikii [3]
To solve this question you need to calculate the number of the gas molecule. The calculation would be:
PV=nRT
n=PV/RT
n= 1 atm * 40 L/ (0.082 L atm mol-1K-<span>1 * 298.15K)
</span>n= 1.636 moles

The volume at bottom of the lake would be:
PV=nRT
V= nRT/P
V= (1.636 mol * 277.15K* 0.082 L atm mol-1K-1 )/ 11 atm= <span>3.38 L</span>
8 0
3 years ago
What is the standard value for T in the common form of the Nernst equation?
LuckyWell [14K]

C.  

52° Celsius

Hope this helped!

6 0
3 years ago
I really need help im stuck
nekit [7.7K]
The first option is the correct.
Since we know the mass of one atom of Fe is 56 and that of Cl2 atoms is 71 (one atom has 35.5 mass) hence both of them will be consumed
3 0
2 years ago
The actual yield of a product in a reaction was measured as 4.20 g. If the theoretical yield of the product for the reaction is
Dmitry_Shevchenko [17]

Answer:

3

Explanation:

remember the equation percentage yield = actual/ theoretical yield as

4.20/4.88 x 100

86.065 so 86.1.

hope this make sense:)

3 0
2 years ago
Precision Problems:
Lorico [155]

Answer:

Precision = 2.70 \± 0.1\ cm

Explanation:

Given

The data in the table

Required

Follow the steps appended to the question;

Step 1: Calculate the Mean or Average

Mean = Summation of lengths divided by number of teams;

Mean = \frac{2.65 + 2.75 + 2.80 + 2.77 + 2.60 + 2.65 + 2.68}{7}\ cm

Mean = \frac{18.9}{7}\ cm

Mean = 2.70\ cm

Step 2: Get The Range

Range = Highest - Lowest

Range = 2.80cm - 2.60cm

Range = 0.2\ cm

Step 3: Divide Range by 2

Approximate\ Range = \frac{1}{2}Range

Approximate\ Range = \frac{1}{2} * 0.2\ cm

Approximate\ Range = 0.1\ cm

Step 4: Determine the Precision

Precision = Average \± Approximate\ Range

Substitute 2.70 for Average and 0.1 for Approximate Range

Precision = 2.70 \± 0.1\ cm

4 0
3 years ago
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