Question

A 0.60-kg object is suspended from the ceiling at the end of a 2.0-m string. When pulled to the side and released, it has a speed of 4.0 m/s at the lowest point of its path. What maximum angle does the string make with the vertical as the object swings up?

Answer 1

Answer:

ø = 53.7º

Explanation:

The measurement of kinetic energy in an object is calculated based on the object's mass and velocity.

KE=1/2mv²

where m is mass

v is velocity

given data

m=0.60 kg

v=4.0 m/s

So

KE = 1/2 . 0.6 . 4^2  

KE= 4.8 J

All the KE is converted into GPE ("Gravitational potential energy (GPE) - energy stored in an object when moving the object to a height")

4.8  = 0.6 . 9.8 . ∆h

∆h  = 0.816 m

This is the height that the object rises.

cos ø  = (2 – 0.816 ) / 2 = 0.592

ø = 53.7º