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VladimirAG [237]
3 years ago
12

Figure 1 shows a wave movement during one second. What is the frequency of the wave

Physics
2 answers:
AURORKA [14]3 years ago
8 0
2 hertz, as explained previously- I'm afraid m/s is a completely different measurement
Andreyy893 years ago
4 0
This is 2 hertz.  You can mark out 2 full wavelengths in the second of time.
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The electric field in a region of space increases from 0 to 2150 N/C in 5.00 s. What is the magnitude of the induced magnetic fi
Feliz [49]

To solve this problem we will use the Ampere-Maxwell law, which   describes the magnetic fields that result from a transmitter wire or loop in electromagnetic surveys. According to Ampere-Maxwell law:

\oint \vec{B}\vec{dl} = \mu_0 \epsilon_0 \frac{d\Phi_E}{dt}

Where,

B= Magnetic Field

l = length

\mu_0 = Vacuum permeability

\epsilon_0 = Vacuum permittivity

Since the change in length (dl) by which the magnetic field moves is equivalent to the perimeter of the circumference and that the electric flow is the rate of change of the electric field by the area, we have to

B(2\pi r) = \mu_0 \epsilon_0 \frac{d(EA)}{dt}

Recall that the speed of light is equivalent to

c^2 = \frac{1}{\mu_0 \epsilon_0}

Then replacing,

B(2\pi r) = \frac{1}{C^2} (\pi r^2) \frac{d(E)}{dt}

B = \frac{r}{2C^2} \frac{dE}{dt}

Our values are given as

dE = 2150N/C

dt = 5s

C = 3*10^8m/s

D = 0.440m \rightarrow r = 0.220m

Replacing we have,

B = \frac{r}{2C^2} \frac{dE}{dt}

B = \frac{0.220}{2(3*10^8)^2} \frac{2150}{5}

B =5.25*10^{-16}T

Therefore the magnetic field around this circular area is B =5.25*10^{-16}T

3 0
2 years ago
What is the final velocity?
Reil [10]
The final velocity is a vector quantity that measures the speed and direction of a moving body after it has reached its maximum acceleration
5 0
3 years ago
Read 2 more answers
What is the acceleration of a block on a ramp inclined 35o to the horizontal if µk = 0.4?
lina2011 [118]
We can solve the problem by applying Newton's second law, which states that the resultant of the forces acting on an object is equal to the product between its mass and its acceleration:
\sum F = ma

We should consider two different directions: the direction perpendicular to the inclined plane and the direction parallel to it. Let's write the equations of the forces along the two directions, decomposing the weight of the object (mg):

mg \sin \theta - \mu_K N = ma (parallel direction) (1)
mg \cos \theta - N =0 (perpendicular direction) (2)
where
\theta=35^{\circ} is the angle of the inclined plane, N is the normal reaction of the plane, \mu_K N is the frictional force, with \mu_K=0.4 being the coefficient of friction.

From eq.(2), we find
N=mg \cos \theta
and if we substitute into eq.(1), we can find the acceleration of the block:
mg \sin \theta - \mu_k mg \cos \theta = ma
from which
a=g(\sin \theta - \mu_K \cos \theta)=(9.81 m/s^2)(\sin 35^{\circ} - 0.4 \cos 35^{\circ})=2.41 m/s^2
7 0
3 years ago
I need someone to help on this number!
Artist 52 [7]
Radioactive decay in the core releases energy. When the sun matter is heated it reduced in density and rises to the surface of the sun, meaning the energy is transferred to the surface.
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3 years ago
I need help the option for D is the golfball isnt accelerating
algol13

Answer:

es b

Explanation:

no se

8 0
3 years ago
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