The Boiling Point of 2-methylpropane is approximately -11.7 °C, while, Boiling Point of <span>2-iodo-2-methylpropane is approximately 100 </span>°C.
As both compounds are Non-polar in nature, So there will be no dipole-dipole interactions between the molecules of said compounds.
The Interactions found in these compounds are London Dispersion Forces.
And among several factors at which London Dispersion Forces depends, one is the size of molecule.
Size of Molecule:
There is direct relation between size of molecule and London Dispersion forces. So, 2-iodo-2-methylpropane containing large atom (i.e. Iodine) experience greater interactions. So, due to greater interactions 2-iodo-2-methylpropane need more energy to separate from its partner molecules, Hence, high temperature is required to boil them.
False. At equilibrium, the rate of forward reaction is equal to the rate of backward reaction. The net concentration of both products and reactants won't change, but the reactions still take place.
Answer:
5 moles
Explanation:
Given data:
Number of moles of HCl = 5 mol
Number of moles of H₂O produced = ?
Solution:
Chemical equation:
HCl + NaOH → NaCl + H₂O
Now we will compare the moles of HCl with H₂O.
HCl : H₂O
1 : 1
5 : 5
5 moles of water will be produced.
The answer is A. when electrons are shared between atoms
Answer:
( dichlorine monoxide ) is Polar Explanation:Answer. Answer = CF2Cl2 (Dichlorodifluoromethane) is Polar What is polar and non-polar? Cl2O ( dichlorine monoxide ) is Polar I'll tell you the polar or nonpolar list below.
