<span>0.70 mol/0.250 L = 2.8 M</span>
Hey there!:
Given the mass of PbCl(OH) :
0.135 Kg = 0.135 Kg*(1000g / 1Kg) = 135 g
Molecular mass of PbCl(OH) = 207+35.5+16+1 = 259.5 g / mol
Atomic mass of Pb = 207 g/mol
Hence mass of Pb in 135 g PbCl(OH) :
(207 g Pb / 259.5 g PbClOH) * 135g PbClOH =
0.79768 * 135 => 107.68 g of Pb
For Pb2Cl2CO3 :
Given the mass of Pb2Cl2CO3 :
0.135 Kg = 0.135 Kgx(1000g / 1Kg) = 135 g
Molecular mass of Pb2Cl2CO3 = 2*207+2*35.5+12+3*16 = 545 g / mol
Mass of Pb present in 1 mol (=545 g / mol) of Pb2Cl2CO3 = 2*207 = 414 g
Hence mass of Pb in 135 g Pb2Cl2CO3:
(414 g Pb / 545 g PbClOH) * 135g PbClOH =
0.75963 * 135 => 102.55 g of Pb2Cl2CO3
Hope that helps!
Answer:
3.62moles
Explanation:
First let us generate a balanced equation for the reaction
2Na + Cl2 —> 2NaCl
Molar Mass of Na = 23g/mol
Mass of Na from the balanced equation = 2 x 23 = 46g
Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol
Mass of NaCl from the balanced equation = 2 x 58.5 = 117g
From the question,
46g of Na produced 117g of NaCl.
Therefore, 83g of Na will produce = (83 x 117)/46 = 211.11g of NaCl
Converting this mass (211.11g of NaCl) to mole, we obtain:
n = Mass /Molar Mass
n = 211.11/ 58.5
3.62moles
Answer:
they are producers and they have means to keep themselves warm
Explanation:
I took test and saw answer.
