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fiasKO [112]
4 years ago
13

Explain the difference in the boiling point of 2-methylpropane and 2-iodo-2-methylpropane in terms of both molecular polarity an

d imf
Chemistry
1 answer:
Len [333]4 years ago
6 0
The Boiling Point of 2-methylpropane is approximately -11.7 °C, while, Boiling Point of <span>2-iodo-2-methylpropane is approximately 100 </span>°C.

As both compounds are Non-polar in nature, So there will be no dipole-dipole interactions between the molecules of said compounds.

The Interactions found in these compounds are London Dispersion Forces.

And among several factors at which London Dispersion Forces depends, one is the size of molecule.

Size of Molecule:
                          There is direct relation between size of molecule and London Dispersion forces. So, 2-iodo-2-methylpropane containing large atom (i.e. Iodine) experience greater interactions. So, due to greater interactions 2-iodo-2-methylpropane need more energy to separate from its partner molecules, Hence, high temperature is required to boil them.
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Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. Show the for
Alexus [3.1K]

Answer:

See explanation below

Explanation:

In this case, let's see both molecules per separate:

In the case of SeO₂ the central atom would be the Se. The Se has oxidation states of 2+, and 4+. In this molecule it's working with the 4+, while oxygen is working with the 2- state. Now, how do we know that Se is working with that state?, simply, let's do an equation for it. We know that this molecule has a formal charge of 0, so:

Se = x

O = -2

x + (-2)*2 = 0

x - 4 = 0

x = +4.

Therefore, Selenium is working with +4 state, the only way to bond this molecule is with a covalent bond, and in the case of the oxygen will be with double bond. See picture below.

In the case of CO₂ happens something similar. Carbon is working with +4 state, so in order to stabilize the charges, it has to be bonded with double bonds with both oxygens. The picture below shows.

5 0
4 years ago
Calcular el valor de la presión osmótica que corresponde a una solución que contiene 2 moles de soluto en un litro de solución a
Brums [2.3K]

El valor de la presión osmótica que corresponde a una solución que contiene 2 moles de soluto en un litro de solución a una temperatura de 17°C es 47.56 atmósferas.

La presión osmótica se puede calcular usando la siguiente ecuación:

\pi = \frac{nRT}{V}   (1)

En donde:

n: es el número de moles = 2 moles

R: es la constante de los gases = 0.082 L*atm/(K*mol)

T: es la temperatura = 17 °C = 290 K

V: es el volumen = 1 L

Introduciendo lo valores anteriores en la ecuación (1), tenemos:

\pi = \frac{nRT}{V} = \frac{2 moles*0.082 L*atm/(K*mol)*290 K}{1 L} = 47.56 atm

Por lo tanto, la presión osmótica es 47.56 atmósferas.

Puedes encontrar más aca:

  • brainly.com/question/5041899?referrer=searchResults
  • brainly.com/question/5925156?referrer=searchResults

Espero que te sea de utilidad!

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3 years ago
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sergejj [24]
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4 years ago
Read 2 more answers
Which is a FALSE statement about compounds?
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3 years ago
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Pls help this a test for Google classroom
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Occurs at a specific temperature

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