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Lady bird [3.3K]
3 years ago
15

Can u explain to me how to do this? This is my first time doing this type of question so explain or give me some of the answers

pls

Chemistry
2 answers:
sergij07 [2.7K]3 years ago
6 0
PH is a number from 0 to 14. From 0 to 7, it would be an acid, with 0 being the strongest. From 7 to 14, it would be a base, with 14 being the strongest base. If a liquid has a pH of 7, it's neutral. I hope that helps!
WITCHER [35]3 years ago
5 0
Bruh bruh bruh bruh bruh bruh
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How many atoms of cobalt are in one formula unit of cobalt (III) oxide? one two three six
IrinaK [193]
I believe the correct answer is the second option. There will be two cobalt atoms in one formula unit of cobalt (III) oxide. It has a chemical formula of Co2O3. This compound is does not naturally occur so it is being synthesized. It is mostly used as bleaching agent.
7 0
3 years ago
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what is the boiling point of a 0.321 m aqueous solution of NaCl. Enter your rounded answer with 3 decimal places.
Ronch [10]

Answer:

I believe the rounded place is 100.333.

3 0
2 years ago
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glucose 6‑phosphate+H2O⟶glucose+Pi glucose 6‑phosphate+H2O⟶glucose+Pi K′eq1=270 K′eq1=270 ATP+glucose⟶ADP+glucose 6‑phosphate AT
ddd [48]

Answer:

-30.7 kj/mol

Explanation:

The standard free energy for the given reaction that is the hydrolysis of ATP is calculated using the formula:  ∆Go ’= -RTln K’eq

where,  

R = -8.315 J / mo

T = 298 K

For reaction,

1. K′eq1=270,

∆Go ’= -RTln K’eq

= - 8.315 x 298 x ln 270

=  - 8.315 x 298 x 5.59

= - 13,851.293 J / mo

= - 13.85 kj/mol

2. K′eq2=890

∆Go ’= -RTln K’eq

= - 8.315 x 298 x ln 890

=  - 8.315 x 298 x 6.79

=  - 16.82 kj/mol

therefore, total standard free energy

= - 13.85 + (-16.82)

=  -30.7 kj/mol

Thus, -30.7 kj/mol is the correct answer.

6 0
3 years ago
What season starts in the northern hemisphere as the suns direct rays strike the equator moving from the southern hemisphere to
laila [671]

Answer:

summer

Explanation:

3 0
3 years ago
A- is a weak base. which equilibrium corresponds to the equilibrium constant ka for ha?
vekshin1

Answer:

K_a=\frac{[H^+][A^-]}{[HA]}

Explanation:

ka is defined as the dissociation constant of an acid. It is defined as the ratio of concentration of products to the concentration of reactants.

For the dissociation of weak acid, the chemical equation follows:

HA\rightleftharpoons H^++A^-

The equilibrium constant is defined by the equilibrium concentration of products over reactants:

K_a=\frac{[H^+][A^-]}{[HA]}

5 0
3 years ago
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