_Mg + _HCL = _MgCl2 + H2
Separate the terms on each side:
_Mg + _HCl = _MgCl2 + H2
Mg- 1 Mg-1
H-1 H-2
Cl-1 Cl-2
Mg is balanced on both sides so move on to the next (put a 1 in the space).
1Mg
There are two H's and two Cl's on the results side, so to balance the equation put a 2 as a coefficient for HCl and it'll all balance out.
2HCl
Balamced equation will be:
1Mg + 2HCL = 1MgCl2 + H2
Metal because it’s more stronger
Last option that is none of above is right answer.
It’s Thai right? I want to help but don’t know how to answer this question.
Answer:
![\\_{2}^{4} \alpha](https://tex.z-dn.net/?f=%5C%5C_%7B2%7D%5E%7B4%7D%20%5Calpha)
Explanation:
In this question, we wish to find the missing nuclei for the equation:
![\\_{92}^{238} U\rightarrow _{90}^{234} Th + _{Z}^{A} X](https://tex.z-dn.net/?f=%5C%5C_%7B92%7D%5E%7B238%7D%20U%5Crightarrow%20_%7B90%7D%5E%7B234%7D%20Th%20%2B%20_%7BZ%7D%5E%7BA%7D%20X)
In order to find the missing species, we need to use the charge and mass balance law. That is, the mass should be conserved: the total mass on the left-hand side with respect to the arrow should be equal to the total mass on the right-hand side with respect to the arrow:
![238 = 234 + A](https://tex.z-dn.net/?f=238%20%3D%20234%20%2B%20A)
Notice from here that:
![A = 238 - 234 = 4](https://tex.z-dn.net/?f=A%20%3D%20238%20-%20234%20%3D%204)
So far we know that the mass of X is 4. Similarly, we apply the law of charge conservation. The total charge should be conserved:
![92=90+Z](https://tex.z-dn.net/?f=92%3D90%2BZ)
From here:
![Z = 92-90=2](https://tex.z-dn.net/?f=Z%20%3D%2092-90%3D2)
We have a particle:
![\\_{2}^{4} X](https://tex.z-dn.net/?f=%5C%5C_%7B2%7D%5E%7B4%7D%20X)
Looking at the periodic table, an atom with Z = 2 corresponds to helium. This can also be written as an alpha particle:
![\\_{2}^{4} \alpha](https://tex.z-dn.net/?f=%5C%5C_%7B2%7D%5E%7B4%7D%20%5Calpha)