1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maxonik [38]
3 years ago
6

I need help in chemistry 10th grade (sophomore)

Chemistry
2 answers:
LuckyWell [14K]3 years ago
6 0

Answer:

Here is the answers I am pretty sure sorry if I am not 100%

Explanation:

1.  2

2. 4

3. 5

4. 2

5. 2

6. 1

7. 3

8. 5

9. 4

10. 4

11. 3

12. 5

13. 6

14. 2

15. 2

16. 1

17. 3

And sorry I am not sure on the rest I did all I could. You have a wonderful day! Please mark brainliest ! Much love to all.

Goryan [66]3 years ago
3 0

Answer:

1) 2

2)4

3)5

4)2

5)2

6)1

7)3

8)5

9)4

10)4

11)3

12)5

13)6

14)2

15)2

16)1

17)2

You might be interested in
Two glucose molecules can combine to form a disaccharide molecule and what molecule
elena-14-01-66 [18.8K]
And a water molecule, this is called a dehydration synthesis. when 2 molecule combine, a water molecule leave.
5 0
3 years ago
In solid NaCl, the equilibrium separation between neighboring Na+ and Cl- ions is 0.283 nm. Calculate the coulombic energy betwe
const2013 [10]

Explanation:

It is given that r = 0.283 nm. As 1 nm = 10^{-9} m.

Hence, 0.283 nm = 0.283 \times 10^{-9} m

  • Formula for coulombic energy is as follows.

             U_{coulomb} = -1.748 \frac{e^{2}}{4 \pi \epsilon_{o} r}

where,   e = 1.6 \times 10^{-19} C

            \epsilon_{o} = 8.85 \times 10^{-12}

          U_{coulomb} = -1.748 \frac{(1.6 \times 10^{-19}^{2}}{4 \times 3.14 \times 8.85 \times 10^{-12} \times 0.283 \times 10^{-9}}

                         = 1.423 \times 10^{-18} J

  • As 1 eV = 1.6 \times 10^{-19} J

So,       1 J = \frac{1 eV}{1.6 \times 10^{-19}}

Hence,    U = \frac{1.423 \times 10^{-18} J}{1.6 \times 10^{-19} J}

                   = 8.9 eV

  • Also,   1 J = \frac{10^{-3} kJ}{6.022 \times 10^{23}mol}

                = 1.67 \times 10^{-27} kJ/mol

Therefore, U = 1.423 \times 10^{-18} J \times 1.67 \times 10^{-27} kJ/mol

                     = 2.37 \times 10^{-45} kJ/mol

7 0
3 years ago
how many grams of oxygen gas are needed to produce 10.0 grams of carbon dioxide according to the balanced equation of CH4
Alinara [238K]
Molar mass of :

O2 = 16 * 2 = 32 g/mol

CO2 = 12 + 16 * 2 = 44 g/mol

<span>Balanced chemical equation :
</span>
1 CH4 + 2 O2 = 1 CO2 + 2 H2O
               ↓              ↓
             2 moles     1 mole

2* 32 g O2 ----------> 1* 44 g CO2
     x g O2 ------------> 10.0 g CO2

44 x = 2 * 32*10.0

44 x = 640

x =  \frac{640}{44}

x = 14.54 g of O2





7 0
3 years ago
Which questions would help determine whether an article is scientifically accurate?
-BARSIC- [3]
I think it would be:
Is the author stating fact or opinion?
Does the author have evidence for the given facts?

Maybe
How many article has the author written before?

Ones you add if you wanted to is
Does the author give any sources? (Like where they got the info)
3 0
3 years ago
Read 2 more answers
The common name for the compound ch3ch2ch2 och2ch3 is
Diano4ka-milaya [45]
Caesium sulfate (cesium sulfate) is the inorganic compound and salt with the formula Cs2SO4. It is a white water-soluble solid that is used to prepare dense aqueous solutions for use in isopycnic (or "density-gradient") centrifugation. It is isostructural with potassium salt.
4 0
3 years ago
Other questions:
  • Determine how many moles are present in 0.23kg of SO(2)
    13·1 answer
  • 4. Imagine you have a radioactive sample containing both Virtualium and decayed atoms of Virtualium. After analysis, you find it
    14·1 answer
  • Which best describes how sediment forms?
    10·1 answer
  • Refer to the given oxidation-reduction reaction, which takes place in acidic solution: MnO₄⁻(aq) + Br⁻(aq) → MnO₂(s) + BrO₃⁻(aq)
    12·1 answer
  • you just got home from a run on a hot Atlanta afternoon. you grab a 1.00-liter bottle of water and drink three-quarters of it in
    6·1 answer
  • How can density be used to identify an object?
    5·1 answer
  • What is the osmotic pressure, in torr, of a 3.00% solution of NaCl in water when the temperature of the solution is 45 ºC? Enter
    14·1 answer
  • The procedure for an experiment is _____.
    8·2 answers
  • 5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure<br> water?
    15·1 answer
  • If the temperature of a gas remains blank the speed of particles will remain blank
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!