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3 years ago

I need help in chemistry 10th grade (sophomore)

Chemistry

2 answers:

LuckyWell [14K]3 years ago

6 0

Answer:

Here is the answers I am pretty sure sorry if I am not 100%

Explanation:

1. 2

2. 4

3. 5

4. 2

5. 2

6. 1

7. 3

8. 5

9. 4

10. 4

11. 3

12. 5

13. 6

14. 2

15. 2

16. 1

17. 3

And sorry I am not sure on the rest I did all I could. You have a wonderful day! Please mark brainliest ! Much love to all.

Goryan [66]3 years ago

3 0

Answer:

1) 2

2)4

3)5

4)2

5)2

6)1

7)3

8)5

9)4

10)4

11)3

12)5

13)6

14)2

15)2

16)1

17)2

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A 25.0-mL sample containing Cu2+ gave an instrument signal of 25.2 units (corrected for a blank). When exactly 0.500 mL of 0.027

irga5000 [103]

Answer:

The molar concentration of Cu²⁺ in the initial solution is 6.964x10⁻⁴ M.

Explanation:

The first step to solving this problem is calculating the number of moles of Cu(NO₃)₂ added to the solution:

$C = \frac{n}{V} \\0.0275 = \frac{n}{0.0005} \\$

n = 1.375x10⁻⁵ mol

The second step is relating the number of moles to the signal. We know the the n calculated before is equivalent to a signal increase of 19.9 units (45.1-25.2):

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3 years ago

A possible mechanism for the gas phase reaction of NO and H2 is as follows: Step 1 2NO N2O2 Step 2 N2O2 + H2 N2O + H2O Step 3 N2

mel-nik [20]

Answer: Option (d) is the correct answer.

Explanation:

Steps involved for the given reaction will be as follows.

Step 1: $2NO \Leftrightarrow N_{2}O_{2}$ (fast)

Rate expression for step 1 is as follows.

Rate = k $[NO]^{2}$

Step 2: $N_{2}O_{2} + H_{2} \rightarrow N_{2}O + H_{2}O$

This step 2 is a slow step. Hence, it is a rate determining step.

Step 3. $N_{2}O + H_{2} \rightarrow N_{2} + H_{2}O$ (fast)

Here, $N_{2}O_{2}$ is intermediate in nature.

All the steps are bimolecular and it is a second order reaction. Also, there is no catalyst present in this reaction.

Thus, we can conclude that the statement step 1 is the rate determining step, concerning this mechanism is not directly supported by the information provided.

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3 years ago

B. What useful functions do oxidation numbers

disa [49]

Explanation:

b. What useful functions do oxidation numbers serve?

It is used to show oxidation and reduction (loss and gain of electrons)

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This is the mass of an element divided by the number of moles.

Molar mass = Mass / Number of moles

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Uranium = 238.03 amu

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3 years ago