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2 years ago

A sophomore class sold a total of 700

Mathematics

1 answer:

mihalych1998 [28]2 years ago

4 0

700 what and how much did they cost? the problem wasnt typed out right

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Please help me no links or I WILL report you thank you in advance

mafiozo [28]

Answer:

the answer is 24 because if you 6 x 4 it's 24

also with 4x6 it's still 24

plz give me a brailnliess

Step-by-step explanation:

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1 year ago

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Factor the GCF: 21x3y4 + 15x2y2 − 12xy3.

-Dominant- [34]

Ugh, these questions.

21x^3y^4 + 15x^2y^2 - 12xy^3

3xy^2 (7x^2y^2 + 5x - 4y)

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3xy² (7x²y² + 5x - 4y)

That's your answer. Thanks for working my brain. ;)

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2 years ago

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B-5=-2. Plz need answer asap b=what???plzzz 6

ruslelena [56]

Answer:

B=-2+5 collecting like terms

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2 years ago

g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur

sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

$\displaystyle V = \pi r^2h$

Substitute:

$\displaystyle (300) = \pi r^2 h$

Solve for h:

$\displaystyle \frac{300}{\pi r^2} = h$

Recall that the surface area of a cylinder is given by:

$\displaystyle A = 2\pi r^2 + 2\pi rh$

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for h.

$\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r} \end{aligned}$

Find its derivative:

$\displaystyle A' = 4\pi r - \frac{600}{r^2}$

Solve for its zero(s):

$\displaystyle \begin{aligned} (0) &= 4\pi r - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}$

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

$\displaystyle \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2} \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm} \end{aligned}$

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

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2 years ago

-2.1x3.2+4.3x(-1.5) what is the answer with solution please

puteri [66]

Answer:

−0.42x^3 −6.45x

Step-by-step explanation:

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2 years ago

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