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prisoha [69]
2 years ago
6

Two bricks are released at the same time from the same point ten feet above the ground. One of the bricks is falling straight do

wn. The other brick is falling like a projectile. Which brick will hit the ground first ? EXPLAIN YOU ASWER PLZZZZ
Physics
1 answer:
natita [175]2 years ago
7 0
Both bricks will hit the ground at the same time.

Falling vertically is always accelerating at 9.8 m/s² because of gravity.
Nothing that's happening horizontally has any effect on that.
The brick that happens to have some horizontal motion will 
probably hit the ground way over there, but that will still be
at the same TIME as this one.

This is a perfect place to remind you of the old unbelievable story,
which I'll bet you heard before:

If you fire a bullet horizontally from a gun, and at the exact same
moment you DROP another bullet out of your hand next to the gun,
the two bullets will hit the ground at the same time !  Even though
they'll be far apart.

Horizontal speed has no effect on vertical behavior.
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Reactive elements such as alkali metals and halogens are found in nature only as
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Compounds

Explanation:

Reactive elements such as alkali metals and halogens are found in nature only as compounds. Such elements are too unstable to remain as stable atoms, therefore they readily combine and form compounds.

  • Compounds are formed when two atoms combines together to share electrons.
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  • In the end, they end up becoming more stable.
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  • Unstable elements are very reactive especially alkali metals and halogens.
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Learn more:

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4 0
3 years ago
Help i forgot to complete this worksheet
Naily [24]

just search up the answer/ definition to all of them, rephrase into own words, then do the same for examples.

6 0
3 years ago
The best rebounders in basketball have a vertical leap (that is, the vertical movement of a fixed point on their body) of about
nadya68 [22]

Answer:

a) 4.45 m/s

b) 0.9 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -9.81\times 1}\\\Rightarrow u=4.45\ m/s

a) The vertical speed when the player leaves the ground is 4.45 m/s

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-4.45}{-9.81}\\\Rightarrow t=0.45\ s

Time taken to reach the maximum height is 0.45 seconds

s=ut+\frac{1}{2}at^2\\\Rightarrow 1=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{1\times 2}{9.81}}\\\Rightarrow t=0.45\ s

Time taken to reach the ground from the maximum height is 0.45 seconds

b) Time the player stayed in the air is 0.45+0.45 = 0.9 seconds

6 0
3 years ago
A heavy boy and a lightweight girl are balanced on a mass-less seesaw. If they both move forward so that they are one-half their
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Answer:

b) Nothing will happen,  the sea saw will still be balanced.

Explanation:

b) Nothing will happen,  the sea saw will still be balanced.

Reason:-

When two kids are balanced, the sum of torques on the seesaw will be zero.

if each kid, reduces their distances by half, then the torque of each kid will be half and the sum of torque of each on the seesaw will be zero.

Therefore the seesaw is balanced

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