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prisoha [69]
3 years ago
6

Two bricks are released at the same time from the same point ten feet above the ground. One of the bricks is falling straight do

wn. The other brick is falling like a projectile. Which brick will hit the ground first ? EXPLAIN YOU ASWER PLZZZZ
Physics
1 answer:
natita [175]3 years ago
7 0
Both bricks will hit the ground at the same time.

Falling vertically is always accelerating at 9.8 m/s² because of gravity.
Nothing that's happening horizontally has any effect on that.
The brick that happens to have some horizontal motion will 
probably hit the ground way over there, but that will still be
at the same TIME as this one.

This is a perfect place to remind you of the old unbelievable story,
which I'll bet you heard before:

If you fire a bullet horizontally from a gun, and at the exact same
moment you DROP another bullet out of your hand next to the gun,
the two bullets will hit the ground at the same time !  Even though
they'll be far apart.

Horizontal speed has no effect on vertical behavior.
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Your GPS shows that your friend’s house is 10.0 km away. But there is a big hill between your houses and you don’t want to bike
kati45 [8]

Answer:

The value is c  = 8 \  km

Explanation:

From the question we are told that

The distance of friends house from your point is a =  10 \  km

The distance of your friends street from your street is b =  6 \  km \  in the \ direction \  towards \  the  \  north

The diagram illustrating this question is shown on the first uploaded image

From the diagram we can apply by Pythagoras theorem as follows

a^2 =  b^2 +  c^2

=>     c  =  \sqrt{^2 -  b^2}

=>     c  =  \sqrt{ 10^2 -  6^2}

=>     c  = 8 \  km

6 0
3 years ago
Calculate the change in length of concrete sidewalk (coefficient of linear expansion for concrete is 12*10^-6/celcius) that is 1
anyanavicka [17]

Answer:

The answer to your question is 5.4 cm

Explanation:

This problem refers to calculate the change in length in one dimension due to a change in temperature.

Data

α = 12 x 10⁻⁶

Lo = 150 meters

ΔT = 30 °C

Formula

                    ΔL/Lo = αΔT

solve for ΔL

                    ΔL = αLoΔT

Substitution

                    ΔL = (12 x 10⁻⁶)(150)(30)

Simplification

                    ΔL = 0054 m = 5.4 cm

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the pygmy shrew has an average mass of 2.0 g if 49 of these shrew are placed on a spring scale with a spring constant of 24 N/m
olga_2 [115]

Answer:

Spring's displacement, x = -0.04 meters.

Explanation:

Let the spring's displacement be x.

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Number of shrews, n = 49

Spring constant, k = 24 N/m

We know that acceleration due to gravity, g is equal to 9.8 m/s².

To find the spring's displacement;

At equilibrium position:

Fnet = Felastic + Fg = 0

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Total mass, Mt = nm

Fg = -Mt = -nmg

-kx -nmg = 0

Rearranging, we have;

kx = -nmg

Making x the subject of formula, we have;

x = \frac {-nmg}{k}

Substituting into the formula, we have;

x = \frac {-49*0.002*9.8}{24}

x = \frac {-0.9604}{24}

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Therefore, the spring's displacement is -0.04 meters.

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A sound wave leaves the loudspeaker. As it travels, it experiences a temporary increase in wavelength and then returns to its original wavelength.  The sound wave traveled through a helium balloon (helium is less dense than air could explain this change in wavelength

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A high-pressure and a low-pressure zone are created in the medium as a result of this constant back and forth action. Compressions and rarefactions, respectively, are terms used to describe these high- and low-pressure zones. The sound waves go from one medium to another as a result of these regions being transmitted to the surrounding media.

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