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tester [92]
3 years ago
6

HNO3 (aq) + H20 (1) ► NO3- (aq) + H30+ (aq)

Physics
1 answer:
vodomira [7]3 years ago
8 0

Answer:

It's H3O+.

Explanation:

The H3O+ ion in the solution is what gives it its acidic properties ( sour taste, low pH , for example). Its known as the hydronium ion.

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A toy rocket moving vertically upward passes by a 2.0-m-high window whose sill is 8.0 m above the ground. The rocket takes 0.15
sveta [45]

Answer:

v_i = 18.86 m/s

Explanation:

As we know that the speed of the rocket is v1 and v2 at the bottom and top of the window

then we will have

d = (\frac{v_1 + v_2}{2}) t

2 = (\frac{v_1 + v_2}{2})(0.15)

26.67 m/s = v_1 + v_2

also we know that

v_2 - v_1 = (-9.81)(t)

v_2 - v_1 = (-9.81)(0.15) = -1.47

now we have

v_2 = 12.6

also we have

v_1 = 14.1 m/s

now if the sill of the window is at height 8 m from the ground then we have

v_1^2 - v_i^2 = 2 a h

(14.1^2) - v_i^2 = 2(-9.81)(8)

v_i = 18.86 m/s

8 0
3 years ago
A sphere has______ sides​
Alina [70]

Answer:

5738929292

Explanation:

simple math

8 0
3 years ago
Read 2 more answers
In space movies, spacecrafts explode and oxygen is needed for a fire to start. Why is it wrong? What would really happen?
Triss [41]

Answer:

Hey

The reason these "space movies" are wrong is because objects in "space" (not in a "space" craft) can't catch on fire because there is no air in "space".

6 0
3 years ago
A speed-time graph is shown below:
VladimirAG [237]

Answer: 0.5 m/s^{2}

Explanation:

Average acceleration a_{ave} is the variation of velocity \Delta V over a specified period of time \Delta t:

a_{ave}=\frac{\Delta V}{\Delta t}}

Where:

\Delta V=V_{f}-V_{o} being V_{o}=0 cm/s the initial velocity and V_{f}=4 cm/s the final velocity  (according to the information given from the described graph)

\Delta t=8 s

Then:

a_{ave}=\frac{4 cm/s -0 cm/s}{8 s}}

a_{ave}=0.5 m/s^{2}

5 0
2 years ago
an Olympic runner leaps over a hurdle.if the runner initial vertical speed is 2.2m/s how much will the runners center of mass be
Snowcat [4.5K]
Supposing the runner is condensed to a point and moves upward at 2.2 m/s.
It takes a time = 2.2/g = 2.2/9.8 = 0.22 seconds to increase to max height. 
Now looking at this condition in opposite - that is the runner is at max height and drops back to earth in 0.22 s (symmetry of this kind of motion). 
From what height does any object take 0.22 s to fall to earth (supposing there is no air friction)? 
d = 1/2gt²= (0.5)(9.8)(0.22)²= 0.24 m
7 0
3 years ago
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