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tester [92]
3 years ago
6

HNO3 (aq) + H20 (1) ► NO3- (aq) + H30+ (aq)

Physics
1 answer:
vodomira [7]3 years ago
8 0

Answer:

It's H3O+.

Explanation:

The H3O+ ion in the solution is what gives it its acidic properties ( sour taste, low pH , for example). Its known as the hydronium ion.

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Calculate the frequency of a wave using an equation​
Gemiola [76]

Answer:

1. f=1T. where: f is the frequency of the wave in hertz. T is the period of the wave in seconds.

2. f=vλ where: f is the frequency of the wave in hertz. v is the velocity of the wave in meters per second. λ is the wavelength of the wave in meters

3. f=cλ

Explanation:

8 0
3 years ago
Answer the following questions
zaharov [31]

Answer:

9 - 10N to the left

10 - There is no change on the object

Explanation:

Can I have brainliest answer pls?

7 0
3 years ago
Read 2 more answers
A parallel-plate, air-gap capacitor has a capacitance of 0.14 mu F. The plates are 0.5 mm apart, What is the area of each plate?
Marysya12 [62]

Answer:

7.9060 m²

8.57 Volts

5.142×10⁻⁶ Joule

1.2×10⁻⁶ Coulomb

Explanation:

C = Capacitance between plates = 0.14 μF = 0.14×10⁻⁶ F

d = Distance between plates = 0.5 mm = 0.5×10⁻³ m

Q = Charge = 1.2 μC = 1.2×10⁻⁶ C

ε₀ = Permittivity = 8.854×10⁻¹² F/m

Capacitance

C=\frac{\epsilon_{0}A}{d}\\\Rightarrow A=\frac{Cd}{\epsilon_{0}}\\\Rightarrow A=\frac{0.14\times 10^{-6}\times 0.5\times 10^{-3}}{8.854\times 10^{-12}}\\\Rightarrow A=7.9060\ m^2

∴ Area of each plate is 7.9060 m²

Voltage

V=\frac{Q}{C}\\\Rightarrow V=\frac{1.2\times 10^{-6}}{0.14\times 10^{-6}}\\\Rightarrow V=8.57\ Volts

∴ Potential difference between the plates if the capacitor is charged to 1.2 μC  is 8.57 Volts.

Energy stored

E=0.5CV²

⇒E = 0.5×0.14×10⁻⁶×8.57²

⇒E = 5.142×10⁻⁶ Joule

∴ Stored energy is 5.142×10⁻⁶ Joule

Charge

Q = CV

⇒Q = 0.14×10⁻⁶×8.57

⇒Q = 1.2×10⁻⁶ C

∴ Charge the capacitor carries before a spark occurs between the two plates is 1.2×10⁻⁶ Coulomb

6 0
3 years ago
The electron in a ground-state h atom absorbs a photon of wavelength 97. 25 nm. to what energy level does the electron move?
Alecsey [184]

The electron in a ground-state H atom absorbs a photon of wavelength 97. 25 nm.  Energy level till where the electron move is 4

Rydberg's equation is formula which signifies relation of wavelength of incident photon and the energy level.

Rydberg's equation is used to find out the relation between the wavelength and the Energy Levels:

1/λ = RZ² (1/n₁² - 1/n₂²)

where, λ is wavelength = 97.25 nm

           R is the Rydberg constant = 1.0967 × 10⁷ m

           n₁ is the initial energy level i.e. the Ground state, n₁  = 1

           n₂ is the higher energy level

On substitution of the above value:

1/97.25 × 10⁻⁹ = 1.0967 × 10⁷ ( 1 -  1/n₂²)

On solving,

⇒ n₂ = 4

Hence, the higher energy level is 4

Learn more about Energy Level here, brainly.com/question/17396431

#SPJ4

5 0
1 year ago
A current of 1.8 A delivers 2.5 C of charge. How much time was required? 0.70 s 0.72 s 1.4 s 4.5 s
Natalka [10]

Answer:

1.4 s

Explanation:

Given the following data;

Quantity of charge, Q = 2.5 C

Current = 1.8 A

To find the time required;

Mathematically, the quantity of charge passing through a conductor is given by the formula;

Quantity of charge, Q = current * time

Substituting into the formula, we have;

2.5 = 1.8 * time

Time = 2.5/1.8

Time = 1.4 s

5 0
3 years ago
Read 2 more answers
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