Answer:
52.2 g
Explanation:
Step 1: Write the balanced equation
3 KOH + H₃PO₄ ⟶ K₃PO₄ + 3 H₂O
Step 2: Calculate the moles corresponding to 89.7 g of KOH
The molar mass of KOH is 56.11 g/mol.
89.7 g × 1 mol/56.11 g = 1.60 mol
Step 3: Calculate the moles of H₃PO₄ needed to react with 1.60 moles of KOH
The molar ratio of KOH to H₃PO₄ is 3:1. The moles of H₃PO₄ needed are 1/3 × 1.60 mol = 0.533 mol.
Step 4: Calculate the mass corresponding to 0.533 moles of H₃PO₄
The molar mass of H₃PO₄ is 97.99 g/mol.
0.533 mol × 97.99 g/mol = 52.2 g
A neutral atom contains the same number of electrons as protons and that means that the electric charge of the atom is neutral or otherwise known as zero. However, if a particular atom loses an electron, the atom becomes positively charged because there is more protons than electrons.
THIS IS CALLED A CATION.
hope this helps x
A higher concentration of reactants leads to more collisions per unit time and leads to an increasing reaction rate. Changing the pressure of gaseous reactants is, in effect, changing their concentration. The increased number of collisions caused by a higher pressure generally increases the reaction rate.
In order to make up 500 mL of a 0.500 M solution, you need a mass of 27.7 g :)
Answer:
C2H4
Explanation:
This compound has no oxygen atoms at all.
