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steposvetlana [31]
3 years ago
8

How many moles of OH−(aq) (hydroxide ions)are present in the balanced redox reaction?

Chemistry
1 answer:
Kobotan [32]3 years ago
4 0
There are 4 moles of (aq) showed in the reaction i think
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PLEASE HELP!!!!!!!!!! DOING A TEST
Nastasia [14]
D is the correct answer
4 0
3 years ago
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The point on a magnet Where magnet effect is strongest is called ​
notsponge [240]

Pole

Explanation:

A magnetic pole is the point on a magnet where a magnet effect is strongest. Around a magnet, there are magnetic fields.

  • The magnetic fields are force fields that leaves the north poles and enters through the south.
  • The pole is where magnetic effects are the strongest.
  • It is around the pole that the strongest magnetic effect on a magnet or magnetic material is felt.
  • The strength of magnetic fields are strongest at the poles.

learn more:

electromagnet brainly.com/question/2191993

#learnwithBrainly

5 0
4 years ago
Exactly 15.0 g of a substance can be dissolved in 150.0 g of water what is the solubility of the substance in grams per 100 g of
Leokris [45]
<span>(15.0 g) / (150.0 g) x (100 g) = 10.0 g/100 g H2O </span>
5 0
3 years ago
How many grams are in 3.14 x 1015 molecules of CO?
Vesnalui [34]

Answer:

Explanation:

Not Many

1 mol of CO has a mass of

C = 12

O = 16

1 mol = 28 grams.

1 mol of molecules = 6.02 * 10^23

x mol of molecules = 3.14 * 10^15        Cross multiply

6.02*10^23 x = 1 * 3.14 * 10^15             Divide by 6.02*10^23

x = 3.14*10^15 / 6.02*10^23

x = 0.000000005 mols

x = 5*10^-9

1 mol of CO has a mass of 28

5*10^-9 mol of CO has a mass of x                        Cross Multiply

x = 5 * 10^-9 * 28

x = 1.46 * 10^-7 grams

Answer: there are 1.46 * 10-7 grams of CO if only 3.14 * 10^15 molecules are in the sample

5 0
3 years ago
A chemist makes up a solution by dissolving 42.0 g of Mg(NO3)2 in enough water to produce a final solution volume of 259 mL. To
Igoryamba

Answer:

The molar mass of Mg(NO₃)₂, 148.3 g/mol.

Explanation:

Step 1: Given data

  • Mass of Mg(NO₃)₂ (solute): 42.0 g
  • Volume of solution: 259 mL = 0.259 L

Step 2: Calculate the moles of solute

To calculate the moles of solute, we need to know the molar mass of Mg(NO₃)₂, 148.3 g/mol.

42.0 g × 1 mol/148.3 g = 0.283 mol

Step 3: Calculate the molarity of the solution

M = moles of solute / liters of solution

M = 0.283 mol / 0.259 L

M = 1.09 M

7 0
3 years ago
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