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3 years ago

300 Jules energy are used to push an object with a force of 75N. what is the maximum distance the object can move?

Physics

1 answer:

Artyom0805 [142]3 years ago

6 0

Energy consumed in doing the work = 300 Joules

Force applied on the object = 75 N

Let the distance moved by the object be d.

Work done by the force is determined by the force applied and the displacement happened in the direction of the force applied.

Work done = Force x displacement

300 = 75 x d

$d = \frac{300}{75}$

d = 4 m

Hence, the maximum distance moved by the object = 4 meters

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A sound source is located somewhere along the x-axis. Experiments show that the same wave front simultaneously reaches listeners

guapka [62]

Answer:

a) x₀ = - 2 m , b) y = 4.47 m

Explanation:

A wave travels in the middle with constant speed, let's use the equation of uniform motion

v = d / t

t = d / v

The distance to the first listeners, see attached

d₁ = x₀-x

t = (x₀ +7) / v

The distance to the second listener

d₂ = x - x₀

t = (+ 3- x₀) / v

As the wave arrives at the same time, we can equal the two equations

(x₀ +7) / v = (3 -x₀) / v

x₀ + 7 = 3 - x₀

2 x₀ = 3 - 7

x₀ = -4/2

x₀ = - 2 m

b) The time it takes for the wave to reach the listeners of the x-axis, where the speed of sound is 340 m / s

t = 5/340

t = 0.0147 s

Let's look for the distance the wave travels for the listener axis and

v = d₃ / t

d₃ = v.t

d₃ = 340 * 0.0147

d₃ = 5 m

For the distance component we use the Pythagorean triangle

d₃² = x₀² + y²

y² = d₃² - x₀²

y = √ (d₃² -4)

y = √ (5² -4)

y = 4.47 m

6 0

3 years ago

Will give correct answer brainliest

sineoko [7]

$200 \times 80\%$

<h2>calculate</h2>

$200 \times \frac{80}{100}$

<h2>reduce the numbers</h2>

$2 \times 80$

<h2>multiply</h2>

$= 160$

<h2>there for we have a solution to the equation</h2>

hope it helps

#carry on learning

mark me as brainlist plss

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I really need Brainliest i am desprate

kondor19780726 [428]

Hy tikki! I've asked some questions, so of you find the questions as easy, then answer it. I'll surely mark you as brainliest :)

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