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aivan3 [116]
3 years ago
12

What caused the formation of the East African Rift Zone?

Physics
2 answers:
Elena-2011 [213]3 years ago
4 0

Answer: divergent plate

Explanation: the East African Rift Valley (EAR) is a developing divergent plate boundary in East Africa. Here the eastern portion of Africa, the Somalian plate, is pulling away from the rest of the continent, which comprises the Nubian plate.

koban [17]3 years ago
4 0

Answer:

Lake Victoria sits between these two branches. It is thought that these rifts are generally following old sutures between ancient continental masses that collided billions of years ago to form the African craton and that the split around the Lake Victoria region occurred due to the presence of a small core of ancient metamorphic rock, the Tanzania craton, that was too hard for the rift to tear through. Because the rift could not go straight through this area, it instead diverged around it leading to the two branches that can be seen today.

Explanation:

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Mamont248 [21]
Answer is 5 watts.


Using the equation:
w=pt

W = work done (J)
P = power (Watts)
T = Time (s)

Substitute the values into the equation.

100 = 20p

Power = 5 watts
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A person might be using social media in an unhealthy way if:
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Juan is studying a group of cells under a microscope. His teacher tells him that the cells either came from the leaf of a tomato
RoseWind [281]

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3 years ago
What is the acceleration of this object? The object's mass is 60 kg.
slamgirl [31]
We know, F = m*a
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Substitute their values, 
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5 0
4 years ago
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A bullet is fired with a velocity of 100 m/s from the ground at an angle of 60° with the horizontal. Calculate the horizontal ra
seraphim [82]

1) The horizontal range of the bullet is 884 m

2) The maximum height attained by the bullet is 383 m

Explanation:

1)

The motion of the bullet is a projectile motion, which consists of two separate motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction  

From the equation of motions along the x- and y- directions, it is possible to find an expression for the horizontal range covered by a projectile, and it is:

d=\frac{u^2 sin 2\theta}{g}

where

u is the initial speed of the projectile

\theta is the angle of projection

g=9.8 m/s^2 is the acceleration of gravity

For the bullet in the problem, we have

u = 100 m/s (initial speed)

\theta=60^{\circ} (angle)

Solving the equation, we find the horizontal range:

d=\frac{(100)^2sin(2\cdot 60^{\circ})}{9.8}=884 m

2)

To find the maximum height, we have to analyze the vertical motion of the bullet. We can do it by using the following suvat equation:

v_y^2 - u_y^2 = 2as

where

v_y is the vertical velocity of the bullet after having covered a vertical displacement of s

u_y is the initial vertical velocity

a =-g= is the acceleration (negative, since it points downward)

The vertical component of the initial velocity is given by

u_y = u sin\theta

Also, the maximum height s is reached when the vertical velocity becomes zero,

v_y =0

Substituting into the equation and re-arranging for s, we find the maximum height:

s=\frac{u^2 sin^2 \theta}{2g}=\frac{(100)^2(sin 60^{\circ})^2}{2(9.8)}=383 m

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

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4 years ago
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