Answer:
Please find the complete solution in the attached file.
Explanation:
88.98 %
The Balance Chemical Equation is as follow,
2 HCl + Pb(NO₃)₂ → 2 HNO₃ + PbCl₂
According to equation,
331.2 g (1 mole) Pb(NO₃)₂ produces = 278.1 g (1 mole) PbCl₂
So,
870 g of Pb(NO₃)₂ will produce = X g of PbCl₂
Solving for X,
X = (870 g × 278.1 g) ÷ 331.2 g
X = 730.5 g of PbCl₂
Therefore,
Theoretical Yield = 730.5 g
Also as given,
Actual Yield = 650 g
So using following formula for percentage yield,
%age Yield = (Actual Yield / Theoretical Yield) × 100
Putting values,
%age Yield = (650 g / 730.5 g) × 100
%age Yield = 88.98 %
Brianliest please and thank you.
C) elements from the top left and the top right of the periodic table
Answer:
The pH of the solution is 5.31.
Explanation:
Let "
is the dissociation of weak acid - HCN.
The dissociation reaction of HCN is as follows.
Initial C 0 0
Equilibrium c(1- ) c c
Dissociation constant = 
In this case weak acids is very small so, (1- ) is taken as 1.
From the given the concentration = 0.050 M
Substitute the given value.
![[H_{3}O^{+}]=c\alpha](https://tex.z-dn.net/?f=%5BH_%7B3%7DO%5E%7B%2B%7D%5D%3Dc%5Calpha)
![[H_{3}O^{+}]=0.05\times 9.8\times 10^{-4}= 4.9\times10^{-6}](https://tex.z-dn.net/?f=%5BH_%7B3%7DO%5E%7B%2B%7D%5D%3D0.05%5Ctimes%209.8%5Ctimes%2010%5E%7B-4%7D%3D%204.9%5Ctimes10%5E%7B-6%7D)
![pH= -log[H_{3}O^{+}]](https://tex.z-dn.net/?f=pH%3D%20-log%5BH_%7B3%7DO%5E%7B%2B%7D%5D)
![=-log[4.9\times10^{-6}]](https://tex.z-dn.net/?f=%3D-log%5B4.9%5Ctimes10%5E%7B-6%7D%5D)
Therefore, The pH of the solution is 5.31.
Answer:
Alkanes (also saturated hydrocarbons , paraffins ) are acyclic hydrocarbons of a linear or branched structure, containing only simple bonds and forming a homological series with the general formula C n H 2n + 2 .
Explanation:
ll alkanes belong to a larger class of aliphatic hydrocarbons. Alkanes are saturated hydrocarbons, that is, they contain the maximum possible number of hydrogen atoms for a given number of carbon atoms. Each carbon atom in the alkane molecules is in a state of sp 3 - hybridization - all 4 hybrid orbitals of the C atom are identical in shape and energy, 4 bonds are directed to the vertices of the tetrahedron at angles of 109 ° 28 '. C – C bonds are σ bonds characterized by low polarity and polarizability . The C – C bond length is 0.154 nm , the C – H bond length is 0.1087 nm.
The simplest member of the class is methane (CH 4 ). The hydrocarbon with the longest chain — noncontactrictan C 390 H 782 — was synthesized in 1985 by English chemists I. Bidd and MK K. Whiting
