Answer:
The required volume is 1.6 x 10³mL.
Explanation:
When we want to prepare a dilute solution from a concentrated one, we can use the dilution rule to find out the required volume to dilute. This rule states:
C₁ . V₁ = C₂ . V₂
where,
C₁ and V₁ are the concentration and volume of the concentrated solution
C₂ and V₂ are the concentration and volume of the dilute solution
In this case, we want to find out V₁:
C₁ . V₁ = C₂ . V₂
Answer : The number of moles of calcium chloride theoretically produced are, 1.3 moles.
Explanation : Given,
Moles of HCl = 2.6 moles
Moles of = 1.4 moles
Now we have to calculate the limiting and excess reagent.
The given balanced chemical reaction is:
From the balanced reaction we conclude that
As, 2 mole of react with 1 mole of
So, 2.6 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of
From the reaction, we conclude that
As, 2 mole of react to give 1 mole of
So, 2.6 moles of react to give
moles of
Therefore, the number of moles of calcium chloride theoretically produced are, 1.3 moles.
Answer : The volume range in milliliters for the solution is 0.25 - 0.5 mL
Explanation :
We have been given that there are approximately 20 drops per milliliter of water
This information can be used as a conversion factor as
We are using 5-10 drops of the solution.
Let us calculate milliliters in 5 drops.
Similarly, 10 drops would contain
solution.
Therefore the volume range in milliliters for the solution is 0.25 - 0.5 mL