if a ball is accelerated downward at 9.8m/s, by how many meters per second does the object's velocity change every second?
1 answer:
The velocity will change (increase) by 9.8 m/s every second.
Why?
Since the ball is accelerated downward at we can see that the ball is on "free fall". It means that the wall was dropped with no initial speed.
Now, if we want to know by how many meters per second does the object's velocity change every second, we need to understand the units of the acceleration. Let's write the equation of acceleration for better understanding.
So, from the equation we can see that the acceleration is changing the velocity every second.
Hence, if an object has the given acceleration (acceleration due to gravity, 9.8m/s2), it means that its speed will change (increase) by 9.8m/s every second.
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Answer:
v = 5.9 x 10⁷ m/s
Explanation:
The kinetic energy of the electron in terms of potential difference is given as:
--------------- equation (1)
where,
e = charge on electron = 1.6 x 10⁻¹⁹ C
V = Potential Difference = 9.9 KV = 9900 Volts
The kinetic energy in general is given as:
--------- equation (2)
where,
m = mass of electron = 9.1 x 10⁻³¹ kg
v = speed of electron = ?
Therefore, comparing equation (1) and equation (2), we get:
<u>v = 5.9 x 10⁷ m/s</u>
Answer:
244.64m
Explanation:
First, we find the distance traveled with constant velocity. It's simply multiplying velocity time the time that elapsed:
After this, the ball will start traveling with a constant acceleration motion. Due to the fact that the acceleration is the opposite direction to the initial velocity, this motion will have 2 phases:
1. The velocity will start to decrease untill it reaches 0m/s.
2. Then, the velocity will start to increase at the rate of the acceleration.
The distance that the ball travels in the first phase can be found with the following expression:
Where v is the final velocity (0m/s), v_0 is the initial velocity (-8m/s) and a is the acceleration (+9m/s^2). We solve for d:
Now, before finding the distance traveled in the second phase, we need to find the time that took for the velocity to reach 0:
Then, the time of the second phase will be:
Using this, we using the equations for constant acceleration motion in order to calculate the distance traveled in the second phase:
V_0, the initial velocity of the second phase, will be 0 as previously mentioned. X_0, the initial position, will be 0, for simplicity:
So, the total distance covered by this object in meters will be the sum of all the distances we found: