Answer:
Usually the coefficient of friction remains unchanged
Explanation:
The coefficient of friction should in the majority of cases, remain constant no matter what your normal force is. When you apply a greater normal force, the frictional force increases, and your coefficient of friction stays the same. Here's another way to think about it: because the force of friction is equal to the normal force times the coefficient of friction, friction is increased when normal force is increased.
Plus, the coefficient of friction is a property of the materials being "rubbed", and this property usually does not depend on the normal force.
Answer:
constant volicty of the pumper when they hit ground 7.03-/s
The answer is group 18.
Explanation:
Group 18 is known as the Noble Gases. They are the most stable elements because they have a full outer shell of valence electrons, so they have no need to bond with other elements.
Answer:
a) I=35mA
b) P=1.73W
Explanation:
a) The max emf obtained in a rotating coil of N turns is given by:

where N is the number of turns in the coil, B is the magnitude of the magnetic field, A is the area and w is the angular velocity of the coil.
By calculating A and replacing in the formula (1G=10^{-4}T) we get:


Finally, the peak current is given by:

b)
we have that


hope this helps!!
Answer:
<h2> 1.643*10⁻⁴cm</h2>
Explanation:
In a single slit experiment, the distance on a screen from the centre point is expressed as y =
where;
is the first two diffraction minima = 1
is light wavelength
d is the distance of diffraction pattern from the screen
a is the width of the slit
Given
= 460-nm = 460*10⁻⁹m
d = 5.0mm = 5*10⁻³m
a = 1.4mm = 1.4*10⁻³m
Substituting this values into the formula above to get width of the central maximum y;
y = 1*460*10⁻⁹ * 5*10⁻³/1.4*10⁻³
y = 2300*10⁻¹²/1.4*10⁻³
y = 1642.86*10⁻⁹
y = 1.643*10⁻⁶m
Converting the final value to cm,
since 100cm = 1m
x = 1.643*10⁻⁶m
x = 1.643*10⁻⁶ * 100
x = 1.643*10⁻⁴cm
Hence, the width of the central maximum in the diffraction pattern on a screen 5.0 mm away is 1.643*10⁻⁴cm