Distance and amount of charge are factors that determine which of the following quantities?
1 answer:
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So, this is a problem where the accleration is not provided, since it is implied. The only acceleration is acceleration due to gravity (9.8 m/s)
The equation we will use for this problem is
V is the final velocity, V₀ is the initial velocity, a is the acceleration, X is the final height, and X₀ is the starting height.
We can assume that the ball starts on the ground since no height is given, so now we plug our numbers in.
We will use 0 as the final velocity, since the ball will stop moving upwards when it is the highest. We will use -9.8 since that is the acceleration due to gravity and we will use 22m/s as V₀ since that is the starting velocity.
So, the ball will go 24.69 meters up
Answer:
That's just if it's a Flexible collision
The question seems incomplete. The complete text is:
a)What is the angular displacement of the wheel between t = 5 s and t = 15 s
b)What is the angular velocity of the wheel at 15 s
And it refers to the attached figure.
a) 25 rad
The graph shown represent the angular position of the wheel at different times.
Therefore, we can simply calculate the angular displacement between two times by calculating the difference between the angular position at t2 and the angular position at t1.
At , the angular position from the graph is
At , the angular position from the graph is
Therefore, the angular displacement is
2) -5.0 rad/s
For a angular displacement vs time graph, the angular velocity at any time is simply equal to the slope of the curve at that time.
Here we want to calculate the angular velocity at t = 15 s, so we have to calculate the slope at that time.
By noting that the slope is constant in the last part of the motion, we find that the slope between 10 s and 20 s is:
This slope is constant between 10 s and 20 s, so the angular velocity of the wheel at t = 15 s
