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Reil [10]
4 years ago
5

Distance and amount of charge are factors that determine which of the following quantities?

Physics
1 answer:
klemol [59]4 years ago
5 0
<span>Distance, amount of charge, and polarity of charge are factors
that determine the electrostatic forces of attraction or repulsion
between two charged objects.</span>
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A 90.00-kg hockey goalie, at rest in front of the goal, stops a puck (m = 0.16 kg) that is traveling at 30.00 m/s. at what speed
Ivahew [28]
<span>5.3 cm/s This is a matter of conservation of momentum. Since there's no mention of the puck rebounding, I will consider this to be a totally non-elastic collision. So, let's determine the starting momentum of the system. Goalie is at rest, so his momentum is 0. Puck is moving at 30.00 m/s with a mass of 0.16 kg, so: 30.00 m/s * 0.16 kg = 4.8 kg*m/s So the starting momentum is 4.8 kg*m/s moving towards the goal. After the collision, the puck and goalie will have the same momentum. So figure out the mass of the new system: 90.00 kg + 0.16 kg = 90.16 kg And divide the system momentum by the system mass: 4.8 kg*m/s / 90.16 kg = 0.053238687 m/s Finally, round to the least precise datum, so the result to 2 significant figures is 0.053 m/s, or 5.3 cm/s.</span>
6 0
4 years ago
An inner city revitalization zone is a rectangle that is twice as long as it is wide. The width of the region is growing at a ra
lukranit [14]

Answer:

\frac{dA}{dt} = 28800 \ m^2/year

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Geometry</u>

  • Area of a Rectangle: A = lw

<u>Algebra I</u>

  • Exponential Property: w^n \cdot w^m = w^{n + m}

<u>Calculus</u>

Derivatives

Differentiating with respect to time

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Explanation:

<u>Step 1: Define</u>

Area is A = lw

2w = l

w = 300 m

\frac{dw}{dt} = 24 \ m/year

<u>Step 2: Rewrite Equation</u>

  1. Substitute in <em>l</em>:                    A = (2w)w
  2. Multiply:                              A = 2w²

<u>Step 3: Differentiate</u>

<em>Differentiate the new area formula with respect to time.</em>

  1. Differentiate [Basic Power Rule]:                                                                   \frac{dA}{dt} = 2 \cdot 2w^{2-1}\frac{dw}{dt}
  2. Simplify:                                                                                                           \frac{dA}{dt} = 4w\frac{dw}{dt}

<u>Step 4: Find Rate</u>

<em>Use defined variables</em>

  1. Substitute:                    \frac{dA}{dt} = 4(300 \ m)(24 \ m/year)
  2. Multiply:                        \frac{dA}{dt} = (1200 \ m)(24 \ m/year)
  3. Multiply:                        \frac{dA}{dt} = 28800 \ m^2/year
3 0
3 years ago
Read 2 more answers
The difference between experimental technique and procedure
kaheart [24]
A procedure is all the steps used to do an experiment in order. 
<span>the experiment is when you test your hypothesis and is designed to answer your question. </span>
<span>the procedure is all the steps of the experiment.</span>
4 0
4 years ago
The tires of a car make 77 revolutions as the car reduces its speed uniformly from 95.0 km/h to 65.0 km/h. The tires have a diam
nika2105 [10]

Answer:

Explanation:

95.0 km/hr = 26.39 m/s

65 km/hr = 18.06 m/s

Circumference of a tire is 0.9π m

77 revolutions is a distance of

77(0.9π) = 69.3π m

v² = u² + 2as

a = (v² - u²) / 2s

a = (18.06² - 26.39²) / (2(69.3π))

a = -0.85 m/s²

s = (v² - u²) / 2a

s = (0² - 26.39²) / 2(-0.85)

s = 409 m

5 0
3 years ago
Need an answer, please need an answer, please​
Karolina [17]

9514 1404 393

Answer:

  • moderate low: 82
  • moderate high: 112.75
  • vigorous low: 123
  • vigorous high: 174.25

Explanation:

When calculations are repetitive, I find it convenient to use a calculator that can work with tables.

The PMHR is (220 -15) = 205.

Each of the other heart rates is computed as the formula shows. For example, the low moderate heart rate is 205×0.40 = <u> 82 </u> bpm

The other rates are shown in the attached table. They are computed the same way.

6 0
3 years ago
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