Answer:
Part a)
Time to reach the maximum height is given as
B)
Maximum height of the bullet is
C)
Horizontal range of the bullet is
Part d)
Final velocity of the bullet is v = 600 m/s at 30 degree
Explanation:
A) As we know that velocity of the bullet is
v = 600 m/s
So we have
Now time to reach the maximum height is given as
B) As we know that the object have zero final speed in y direction
C)
Now the horizontal displacement of the object in total time of flight is known as range of projectile
So we have
Part d)
As we know that the final height is same as that of initial So it will strike the ground at same velocity as that of initial velocity
So we have
v = 600 m/s at 30 degree
Answer:
Explanation:
v = ω R
v is linear speed and ω is angular speed
ω = v / R
a ) Inner radius = 25 x 10⁻³ m
speed v = 1.25 m/s
ω = 1.25 / (25 x 10⁻³ )
= .05 x 10⁻³
= 5 x 10⁻⁵ rad / s
outer radius = 58 x 10⁻³ m
speed v = 1.25 m/s
ω = 1.25 / (58 x 10⁻³ )
= .0215 x 10⁻³
= 2.15 x 10⁻⁵ rad / s
b )
linear constant speed v = 1.25 m /s
time = 74 min = 74 x 60 s
distance tracked = speed x time
= 1.25 x 74 x 60
= 5550 m
c ) time given
= 74 min = 74 x 60 s
angular acceleration
= ( 2.15 - 5 ) x 10⁻⁵ / (74 x 60 )
= - 6.42 x 10⁻⁹ rad / s²
Plant cells are eukaryotic cells that differ in several key aspects from the cells of other eukaryotic organisms. number two sry but Idk
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The centripetal force is equal to:
After substituting the values from the question into the equation, we get:
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</span>This solves to give a value of 956.25N