Answer:
m = 7.29 grams
Explanation:
Given that,
Initial temperature, T₁ = 25ºC
Final temperature, T₂ = 31.5ºC
The specific heat of the metal is 0.89 J/gºC.
We know that the heat released due to the change in temperature is given by :
![Q=mc\Delta T\\\\m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{42.2 }{0.89\times (31.5-25)}\\\\m=7.29\ g](https://tex.z-dn.net/?f=Q%3Dmc%5CDelta%20T%5C%5C%5C%5Cm%3D%5Cdfrac%7BQ%7D%7Bc%5CDelta%20T%7D%5C%5C%5C%5Cm%3D%5Cdfrac%7B42.2%20%7D%7B0.89%5Ctimes%20%2831.5-25%29%7D%5C%5C%5C%5Cm%3D7.29%5C%20g)
So, the mass of the piece is equal to 7.29 grams.
Answer:
Mass of B-11 = 11.009 amu
Explanation:
Given data:
Abundance of B-10 = 19.9%
Abundance of B-11 = 80.1%
Mass of B-10 = 10.013 amu
Mass of B-11 = ?
Solution:
Average atomic mass of boron is 10.811 amu.
Average atomic mass of boron = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
10.811 = (10.013×19.9) + (x × 80.1) /100
10.811 = 199.26 + (x × 80.1)
10.811 × 100 = 199.26 + (x × 80.1)
1081.1- 199.26 = x × 80.1
881.84 = x × 80.1
881.84/ 80.1 = x
x = 11.009
Oh ok thanks so where the picture
The answer is B.
Tetraphosphorus is written as P4, and decaiodide as I10, so when you put them together, it's P4I10
Answer:
volume = 13097674418.528dm³
Explanation:
n = (3.52)*10^32/(6.02)*10^23)
n = (584717607.97)
n = volume /molar volume
molar volume at stp = 22.4dm³
volume= 584717607.97 x 22.4
volume = 13097674418.528dm³