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Alenkinab [10]
3 years ago
11

can someone help me create my own chemistry meme with this picture.. ( don’t copy and paste from internet please ) THANKS !

Chemistry
2 answers:
Oksana_A [137]3 years ago
6 0
When you mix a whole bunch of random items into a bowl to think you’re a great mad scientist
Flura [38]3 years ago
5 0

Answer:

When you remember salt is soduim chloride so you put it on everything to feel smart.

Explanation:

Sorry im bad at this : - /

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According to the arrhenius concept, an acid is a substance that ________.
nydimaria [60]
An acid is a substance that dissociates in water to produce hydrogen ions or protons.
7 0
3 years ago
What is the order, plz answer
slamgirl [31]

Answer:

C A B

Explanation:

come on, you also know this from normal water waves.

which ones are stronger (= have more energy) ? the small ones or the big ones ?

and the same applies to all waves. the bigger the waves (higher amplitude), the more energy.

7 0
3 years ago
Which of the compounds in the table below is listed in the wrong colum?
Sveta_85 [38]

Answer: C

Explanation: This is because of a nice thing called guessing

5 0
3 years ago
If a sample of gold is a cube what is the length of each edge in centimeters
Irina-Kira [14]
<span>This question cannot be answered in actual centimeters unless at least one edge has a known length however it can be written as (length^3) or (length cubed). As an example if the sample of gold cube had one length of 3cm then all lengths would be 3cm on the cube.</span>
4 0
3 years ago
Find ΔHrxn for the following reaction: <br><br> 2PbS(s)+3O2(g)→2PbO(s)+2SO2(g)
ch4aika [34]

Answer:

ΔH°rxn = -827.5 kJ

Explanation:

Let's consider the following balanced equation.

2 PbS(s) + 3 O₂(g) → 2 PbO(s) + 2 SO₂(g)

We can calculate the standard enthalpy of reaction (ΔH°rxn) from the standard enthalpies of formation (ΔH°f) using the following expression.

ΔH°rxn = [2 mol × ΔH°f(PbO(s)) + 2 mol × ΔH°f(SO₂(g) )] - [2 mol × ΔH°f(PbS(s)) + 3 mol × ΔH°f(O₂(g) )]

ΔH°rxn = [2 mol × ΔH°f(PbO(s)) + 2 mol × ΔH°f(SO₂(g) )] - [2 mol × ΔH°f(PbS(s)) + 3 mol × ΔH°f(O₂(g) )]

ΔH°rxn = [2 mol × (-217.32 kJ/mol) + 2 mol × (-296.83)] - [2 mol × (-100.4) + 3 mol × 0 kJ/mol]

ΔH°rxn = -827.5 kJ

5 0
3 years ago
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