If you increase the steepness of the ramp, then you will increase the acceleration of a ball which rolls down the ramp. This can be seen in two different ways:
<span>1) Components of forces. Forces are vectors and have a direction and a magnitude. The force of gravity points straight down, but a ball rolling down a ramp doesn't go straight down, it follows the ramp. Therefore, only the component of the gravitational force which points along the direction of the ball's motion can accelerate the ball. The other component pushes the ball into the ramp, and the ramp pushes back, so there is no acceleration of the ball into the ramp. If the ramp is horizontal, then the ball does not accelerate, as gravity pushes the ball into the ramp and not along the surface of the ramp. If the ramp is vertical, the ball just drops with acceleration due to gravity. These arguments are changed a bit by the fact that the ball is rolling and not sliding, but that only affects the magnitude of the acceleration but not the fact that it increases with ramp steepness. </span>
<span>2) Work and energy. The change in potential energy of the ball is its mass times the change in height (only the vertical component counts -- horizontal displacements do not change gravitational potential energy) times the local gravitational acceleration g. This loss of gravitational potential energy shows up as an increase in kinetic energy. If the ball falls a farther distance vertically, it will have a greater kinetic energy and be going faster. Again, the kinetic energy is shared between the motion of the ball going somewhere, and the rotation of the ball, and so the details of the acceleration depend on the ball (is it hollow or solid?), but the dependence on the steepness of the ramp is the same. </span>
Answer:
I₁ =1250 kg.m²
Explanation:
Given that
Angular speed of Merry ,ω₁= 0.2 rad/s
Angular speed of technician ,ω₂= 0.04 rad/s
Moment of the inertia of the technician ,I₂= 5000 kg.m²
Lets assume that
Moment of the inertia of merry with respected to the ground=I₁
There is no any external torque ,that is why angular momentum of the system will be conserve.
Now by conserving angular momentum
I₁ ω₁=(I₁+I₂)ω₂
I₁ x 0.2 = (I₁ +5000 ) x 0.04
I₁ (0.2-0.04) = 5000 x 0.04
I₁ =1250 kg.m²
The result is although the wire's resistivity doesn't change, its resistance does.
Considering the formula for a material's resistance:
R=pL/A
R is directly proportional to L and inversely proportional to A, as can be seen. Be aware that "rho" is a material-specific and intensive attribute (meaning this value will not change if the material is only physically altered). Remember that A = This implies that the relationship between R and the square of r is inverse. When the wire is stretched, the impacts on length are less noticeable than the effects on r. Therefore the wire's resistance increases, but its resistivity stays the same.
Learn more about resistance here:
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The gravitational force acting between them is 
Data given;
- M1 = 45kg
- M2 = 11kg
- r = 2.0m
- G =
To solve this question, we need to apply gravitational force or energy formula.
<h3>Gravitational Force</h3>
This states that the force of attraction between two bodies is equal to the product of their bodies and inversely proportional to the square of their distance apart.
Mathematically;
let's substitute the values and solve
The force of gravity acting between them is
Learn more on gravitational force here;
brainly.com/question/11359658
Answer:
By a factor 9
Explanation:
The intensity of a sound wave is proportional to the square of the amplitude of the wave:
where
I is the intensity
A is the amplitude of the wave
In this problem, the amplitude of the sound wave is increased by a factor 3:
A' = 3A
So the intensity would change by
So, the intensity would increase by a factor 9.
