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Zigmanuir [339]
3 years ago
7

For an object in uniform circular motion, what can you say about the directions of the velocity, acceleration, and net force vec

tors? For an object in uniform circular motion, what can you say about the directions of the velocity, acceleration, and net force vectors? The velocity vector is perpendicular to the acceleration vector; the acceleration vector is parallel to the net force vector. The velocity vector is parallel to the acceleration vector; the acceleration vector is parallel to the net force vector. The velocity vector is perpendicular to the acceleration vector; the acceleration vector is perpendicular to the net force vector. The velocity vector is parallel to the acceleration vector; the acceleration vector is perpendicular to the net force v
Physics
1 answer:
tigry1 [53]3 years ago
7 0

Answer: The velocity vector is perpendicular to the acceleration vector; the acceleration vector is parallel to the net force vector.

Explanation:

In a uniform circular motion, the meaning of "uniform"is the same as for an uniform straight motion, i.e., the module of the velocity vector (its speed) is constant.

Now, if the object were not describing a circular trajectory, it should move at constant speed, in a straight line, provided no external forces acted upon it.

If there is an external force acting on it, making it to follow a circular trajectory, this force doesn't change the instantaneous value of the velocity, but it changes his direction instead.

While the direction is changing, it always keep tangential to the trajectory, due to if at any moment the force disappears, the body must continue in a straight line at constant speed, following a line tangent to the circle.

It can be showed, that the acceleration vector, defined as the change in velocity over time, always aims towards the center of the circle, and is perpendicular to the velocity vector.

As the only net force acting on the object (assuming a horizontal trajectory), is the one that causes the acceleration, the acceleration vector has the same direction as the net force.

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Pepsi [2]

Answer:

W =84.6\ Nm

Explanation:

given,

F = 14.1 i + 0 j + 5.1 k

displacement = 6 m

Assuming block is moving in x- direction

we know,

 dW = F dx

\int dW = F\int dx

W = F\int_0^6 dx

W = F[x]_0^6

W = 14.1 \times 6

W =84.6\ Nm

hence, work done by the force is equal to W =84.6\ Nm

7 0
3 years ago
A 5.00 kg mass is placed on top of a vertical spring, which compresses a distance of 3.13 cm. Calculate the force constant (in N
77julia77 [94]

Answer:

<h2>1567.09 N/m</h2>

Explanation:

Step one:

given data

mass m=5kg

compression x= 3.13cm to m= 0.0313m

<em>According to Hooke's law, provided the elastic limit of an elastic material is not exceeded the extension e is directly proportional to the applied force</em>

F=ke

where

k= spring constant in N/m

e= extension/compression in

Step two:

assume g= 9.81m/s^2

F=mg

F=5*9.81

F=49.05N

substitute in the expression F=ke

49.05=k*0.0313

k=49.05/0.0313

k=1567.09 N/m

<u>The force constant (in N/m) of the spring is 1567.09 N/m</u>

8 0
3 years ago
Which electromagnetic waves have the shortest wavelength and the highest frequency?<br><br> waves
ANTONII [103]

Answer:

The correct answer is Gamma Rays.

Explanation:

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Explain how a common housecat gets “worms.”eplain(science)
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Answer:

Cats most commonly contract worms after coming into contact with parasite eggs or infected feces. A cat may walk through an area with eggs or infected feces, and since cats are often such fastidious groomers, they will then ingest the eggs or fecal particles as they clean their fur and feet.

Explanation:

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Some enterprising physics students working on a catapult decide to have a water balloon fight in the school hallway. The ceiling
sergejj [24]

Answer:

\alpha =54.7º

Explanation:

From the exercise we have our initial information

y=3.4m\\v_{o}=10m/s\\g=-9.8m/s^2

When the balloon gets to the ceiling its velocity at that moment is 0 m/s. Being said that we can calculate velocity at the vertical direction

v_{y}^2=v_{oy}^2+ag(y-y_{o})

Since v_{y}=0 and y_{o}=0

0=v_{oy}^2-2(9.8m/s^2)(3.4m)

v_{oy}=\sqrt{2(9.8m/s^2)(3.4m)}=8.16m/s

Knowing that

v_{oy}=v_{o}sin\alpha

sin\alpha =\frac{v_{oy} }{v_{o} }

\alpha =sin^{-1}(\frac{v_{oy}}{v_{o}})=sin^{-1}(\frac{8.16m/s}{10m/s})=54.7º

8 0
3 years ago
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