Someone plz help me with this problem!!!

Anyone that can help???

marissa [1.9K]

Answer:

Explanation:

56) A

57) E

4 0

3 years ago

an object of mass 1 g is hung from a spring and set in oscillatory motion .At t=0 the displacement is 43.75cm and the accelerati

charle [14.2K]

The spring constant is $4.0\cdot 10^{-5} N/m$

Explanation:

For an object in a simple harmonic motion, the acceleration of the object is related to the displacement by

$a=-\omega^2 x$

where

a is the acceleration

$\omega$ is the angular frequency

x is the displacement

The angular frequency is defined as

$\omega=\sqrt{\frac{k}{m}}$

where

k is the spring constant

m is the mass

Substituting the second equation into the first one, we get

$a=-\frac{k}{m}x$

In this problem we have

m = 1 g = 0.001 kg

And at t=0,

x = 43.75 cm

a = -1.754 cm/s

Therefore, we can re-arrange the equation above to find the spring constant:

$k=-\frac{ma}{x}=-\frac{(0.001)(-1.754)}{43.75}=4.0\cdot 10^{-5} N/m$

#LearnwithBrainly

6 0

3 years ago

The atomic radius of metal X is 1.20 × 102 picometers (pm) and a crystal of metal X has a unit cell that is face-centered cubic.

dmitriy555 [2]

The density of the metal can be determined through the formula [n*MW]/ Na*[a^3] . substituting, we get,

d = [n*MW]/ Na*[a^3]
d = [4 atoms*42.3 g/mol]/ [6.022 x 1023atoms/mol* (sqrt 8 *1.20x10-10)^3]
d = 0.719 g/cm3

4 0

4 years ago

explain why radio waves can travel through space,but sound waves cannot.explain the behavior of sound waves and radio waves in s

LUCKY_DIMON [66]

Radio waves can travel through space because it is a radio wave.But sound waves cannot because it is called sounds waves .The behavior of the sounds wave and radio waves in space iws because chocalte are brown.spngebob squarepants are blue.Furthermore,dog can poop and we can poop.Also,this is how you can also explain like this:Radio Waves and Sounds Waves is Science.How i know this because i used my brain and i'm smart'' this is perfect explaination

5 0

3 years ago

(I) A 0.145-kg baseball pitched at 31.0 m/s is hit on a horizontal line drive straight back at the pitcher at 46.0 m/s. If the c

tangare [24]

Answer:

The force between the ball and the bat = 2233 N

Explanation:

Force: This can be defined as the product of force and its acceleration.

The S.I unit of Force is Newton (N)

F = ma .............................. Equation 1

Where F = Force , m = mass of the ball, a = acceleration of the ball.

where

a = (v-u)/t..................... Equation 2

Where v = final velocity of the ball, u = initial velocity of the ball, t = time of contact between the ball an the bat.

Given: v = 46 m/s u = - 31 m/s (it hit an horizontal line drive back at the pitcher), t = 5×10⁻³ s

Substituting these values into equation 2,

a = [46-(31)]/(5×10⁻³ )

a = 77×10³/5

a = 15.4×10³ m/s².

Also given m = 0.145 kg

Substituting into equation 1,

F = 0.145(15.4×10³ )

F = 2233 N

Thus the force between the ball and the bat = 2233 N

8 0

3 years ago