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astra-53 [7]
3 years ago
10

Nagine you are repeatedly lifting a weight into the air up to a height of 2 m. Assuming in each litt

Chemistry
1 answer:
Mariulka [41]3 years ago
8 0

Answer:

A

Explanation:

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Could you please Calculate the number of atom of 40K (potassium 40) in 1gram of KCl. Taking into account the isotopic abundance
Crank

Answer:

9.53*10^{17} atoms of 40K

Explanation:

You can use the molecular mass and the Avogadro´s number, in the following formula:

N_{40K=\frac{m_{KCl}}{M_{MKCl}}}*N_{Avogadro}*(IA_{40k})

where m_{KCl} is the sample mass, M_{KCl} is the molecular mass of the KCl and IA(40K) is the isotopic abundance of 40K.

Now replacing the values, you can find:

N_{40K}=\frac{1g}{74.5513\frac{g}{mol}}*6.022*10^{23}mol^{-1} *0.000118

N_{40K}=9.53*10^{17} atoms

8 0
3 years ago
What is the difference between a rock and a mineral ? Plz only (1-2 sentence) thx sm!
Tasya [4]

A mineral is a naturally occurring inorganic element or compound having an orderly internal structure and characteristic chemical composition, crystal form, and physical properties. ... A rock is an aggregate of one or more minerals, or a body of undifferentiated mineral matter.

4 0
3 years ago
What is one benfit of using ph instead of molar concentrations?
puteri [66]

One benefit of using ph instead of molar concentrations is that since molarity is a rate of “ moles per liter" ,  Molarity (M) is used to measure the concentration of hydrogen ions in a solution, which is used with pH applications. ... The H+ is the molarity number, which shows the concentration of hydrogen ions in the solution.

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3 years ago
Don't know how to solve
faltersainse [42]
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8 0
3 years ago
what is the balanced equation when copper metal is placed in a solution when platnium ii chloride is placed. what is the equatio
koban [17]

Answer:

Cu~+~PtCl_2->Pt~+~CuCl_2

Explanation:

In this case, we can start with the <u>formula of Platinum (II) Chloride</u>. The cation is the atom at the left of the name (in this case Pt^+^2) and the anion is the atom at the right of the name (in this case Cl^-). With this in mind, the <u>formula would be</u> PtCl_2.

Now, if we used <u>metallic copper</u> we have to put in the reaction only the <u>copper atom symbol</u> Cu. So, we have as reagents:

Cu~+~PtCl_2->

The question now is: <u>What would be the products?</u> To answer this, we have to remember <u>"single displacement reactions"</u>. With a general reaction:

A~+~BC->AB~+~C

With this in mind, the reaction would be:

Cu~+~PtCl_2->Pt~+~CuCl_2

I hope it helps!

5 0
2 years ago
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