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irina1246 [14]
3 years ago
8

Calculate the temperature of 2.0 moles of a gas occupying a volume of 5.0 L at 2.46 atm. (R = 0.08125 L atm/mol L)

Chemistry
2 answers:
Serjik [45]3 years ago
7 0

Answer:

Hi how are you doing today Jasmine

belka [17]3 years ago
3 0

Answer: a. 75K

Explanation:

https://socratic.org/answers/200353

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Describe the particles that make up a pure substance
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Answer:

Each element consists of indivisible, minute particles called atoms.

All atoms of a given element are identical.

Atoms of different elements have different masses.

Explanation:

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The graph above shows the progress of a chemical reaction. Based on the graph, which of the following is true?
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I believe the answers b
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According to your study unit, what's the payoff that keeps volunteers using their own time to help their communities?
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8 0
3 years ago
A student obtains a 10.0g sample of a white powder labeled as BaCl2. After completely dissolving the powder in 50.0mL of distill
LekaFEV [45]

Answer:

Whether barium chloride solution was pure

Explanation:

We may answer whether barium chloride was pure. The sequence of this experiment might be depicted by the following balanced chemical equations:

BaCl_2 (aq)\rightarrow Ba^{2+} (aq) + 2 Cl^- (aq)

Ba^{2+} (aq) + SO_4^{2-} (aq)\rightarrow BaSO_4 (s)

Having a total sample of 10.0 grams, we would firstly find the mass percentage of barium in barium chloride:

\omega_{Ba^{2+}} = \frac{M_{Ba}}{M_{BaCl_2}} = \frac{137.327 g/mol}{208.23 g/mol\cdot 100\% = 65.95 \%

This means in 10.0 g, we have a total of:

m_{Ba^{2+}} = 10.0 g\cdot 0.6595 = 6.595 g of barium cations.

The precipitate is then formed and we measure its mass. Having its mass determined, we'll firstly find the percentage of barium in barium sulfate using the same approach:

\omega_{Ba} = \frac{137.327 g/mol}{233.38 g/mol}\cdot 100\% = 58.84 \%

Multiplying the mass we obtained by the fraction of barium will yield mass of barium in barium sulfate. Then:

  • if this number is equal to 6.595 g, we have a pure sample of barium chloride;
  • if this number is lower than 6.595 g, this means we have an impure sample of barium chloride, as we were only able to precipitate a fraction of 6.595 g.
3 0
3 years ago
A student investigated the diffusion of ammonia gas, NH3, and hydrogen chloride gas, HCl. The damp red litmus paper for NH3 chan
Alex Ar [27]

Answer:

43.96secs

Explanation:

M1 = molar mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

t1 = time for NH3 to diffuse = 30secs

M2 = molar mass of HCl = 1 + 35.5 = 36.5g/mol

t2 = time for HCl to diffuse =?

From Graham's law of diffusion:

t2/t1 = √(M2/M1)

t2/30 = √(36.5/17)

t2/30 = 1.465

Cross multiply

t2 = 30 x 1.465

t2 = 43.96secs

Therefore it will take 43.96secs for the damp blue litmus paper to change colour for HCl.

8 0
3 years ago
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