Answer:
The magnitude of the force that each wire exerts on the other will increase by a factor of two.
Explanation:
force on parallel current carrying wire, F = BILsinθ
where;
B is the strength of the magnetic field
L is the length of the wire
I is the magnitude of current on the wire
θ is the angle of inclination of the wire
Assuming B, L and θ is constant, then F ∝ I
F = kI

When the amount of current is doubled in one of the wires, lets say the second wire;

Also, if will double the amount of current on the first wire, then
F₁ = 2F₂
Therefore, the magnitude of the force that each wire exerts on the other will increase by a factor of two.
Answer:
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Explanation:
Answer:
The allowed current in the cable is 1.15 A.
Explanation:
Given that,
Distance = 1.00 m
Suppose the magnetic field is
and if the experiment is to be accurate to 1.0 %
We need to calculate the current
Using formula of magnetic field


Put the value into the formula


If the experiment is to be accurate to 1.0%
Then,
We need to calculate the allowed current in the cable



Hence, The allowed current in the cable is 1.15 A.
Answer:
(a) 
(b) The force is repulsive
Explanation:
a) According to Coulomb's law, the magnitude of the electrice force that one particle exerts on the other is defined as:

Here k is the coulomb constant,
and
are the signed magnitudes of the charges and d is the distance between them.

b) According to Coulomb's law, if the two charges have the same sign, the electrostatic force between them is repulsive.