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andrew11 [14]
3 years ago
9

Y and X vary directly. If the constant of variation is 4,then what is the value of x when y=6?

Mathematics
1 answer:
jarptica [38.1K]3 years ago
6 0

\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ k=4\qquad \boxed{y=4x}\qquad \qquad \textit{when y=6}~\hfill 6=4x\implies \cfrac{6}{4}=x\implies \cfrac{3}{2}=x

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Answer with the explanation step by step
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Answer:

The answer is A. \frac{3(x-21)}{(x+7)(x-7)}.

Step-by-step explanation:

To find the difference of this problem, start by simplifying the denominator, which will look like \frac{3}{x+7}-\frac{42}{(x+7)(x-7)}. Next, multiply \frac{3}{x+7} by \frac{x-7}{x-7}  to create a fraction with a common denominator in order to subtract from \frac{42}{(x+7)(x-7)}. The problem will now look like \frac{3}{x+7}*\frac{x-7}{x-7}-\frac{42}{(x+7)(x-7)}.  

Then, simplify the terms in the problem by first multiplying \frac{3}{x+7} and \frac{x-7}{x-7}, which will look like \frac{3(x-7)}{(x+7)(x-7)}-\frac{42}{(x+7)(x-7)}. The next step is to combine the numerators over the common denominator, which will look like \frac{3(x-7)-42}{(x+7)(x-7)}.

Next, simplify the numerator, and to simplify the numerator start by factoring 3 out of 3(x-7)-42, which will look like \frac{3(x-7-14)}{(x+7)(x-7)}. Then, subtract 14 from -7, which will look like \frac{3(x-21)}{(x+7)(x-7)}. The final answer will be \frac{3(x-21)}{(x+7)(x-7)}.    

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