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3 years ago

Which one is correct ?

Mathematics

2 answers:

Inessa05 [86]3 years ago

8 0

All of them are wrong

Assoli18 [71]3 years ago

7 0

Then which one is the correct answer if they are all wrong? Please answer he question even though the answers are wrong.

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Oliver interviewed 30% of the 9th grade class and 70% of the 10th grade class at his school. Jenny interviewed 75% of the 9th gr

julia-pushkina [17]

Answer:

A. 36

Step-by-step explanation:

We are given a total of 176 interviewed by Oliver and a total of 140 interviewed by Jenny. To find how many more 10th graders than 9th graders were interviewed, subtract the totals given

176 - 140 = 36

This is how we came to the answer:

We are given 70% of the 10th-grade and 30% of the 9th-grade with a total of 176 for Oliver.

While we're given 75% of the 9th-grade class and 25% of the 10th-grade with a total of 140 interviewed by Jenny

Oliver's Interviewees

10-graders

Firstly, let's find what the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

70% of 176 =

Cross multiply

123.2 were 10-graders interviewed by Oliver

9th-graders

Now, to find the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

30% of 176 =

Cross multiply

52.8 were 9th-graders interviewed by Oliver

Jenny's Interviewees

9th-graders

Firstly, let's find what the number of 9th-graders was interviewed by Jenney; find the percentage of the 9th-graders by the total;

75% of 140 =

Cross multiply

105 students were 9th-graders interviewed by Jenney.

10th-graders

Now, to find the number of 10th-graders was interviewed by Jenney; find the percentage of the 10th-graders by the total;

25% of 140 =

Cross multiply

35 students were 10th-graders interviewed by Jenney.

Total calculation

Use the results and sum them up by 9th-grade plus 9th-grade and 10th-grade plus 10-grade. Then subtract the amount gotten from 9th-grade away from the amount gotten from 10th-grade;

Oliver's 9th-grade = 52.8

Jenny's 9th-grade = 105

105 + 52.8 = 157.8

Oliver's 10th-grade = 123.2

Jenny's 10th-grade = 35

123.2 + 35 = 158.2

Total calculation: 158. 2 - 157.8 = 0.4

Therefore, there are 36 more 10th than 9th.

For more information, visit: brainly.com/question/23490909

7 0

2 years ago

Graph this please due today

vaieri [72.5K]

Answer: see last picture

Step-by-step explanation:

We see that the y-intercept is 10 and the slope is -3

so when x = 0, y = 10

Graph this first point (picture 1)

Since the slope is -3, every time you go one unit to the left, you go down 3 units, so graph this second point (picture 2)

Continue this until you have no more room on the graph (picture 3)

now draw a line through the dots (picture 4)

4 0

3 years ago

Find the coordinates of the midpoint of the segment whose endpoints are R(9, 3) and S(-1, -9).

amm1812

Answer:

$(4, -3 )$

General Formulas and Concepts:

Pre-Algebra I

Order of Operations: BPEMDAS

Algebra I

Midpoint Formula: $(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )$

Step-by-step explanation:

Step 1: Define

R (9, 3)

S (-1, -9)

Step 2: Find midpoint

Substitute: $(\frac{9-1}{2}, \frac{3-9}{2} )$
Subtract: $(\frac{8}{2}, \frac{-6}{2} )$
Divide: $(4, -3 )$

4 0

2 years ago

To answer that question

Mars2501 [29]

First, we get ax^2+bx+c. Next, we know that the line of symmetry is -b/2a. Since we know that there is a maximum value, the parabola is facing downwards, so a is negative. For random numbers, we can say that a = -0.5 and b=-10 (b needs to be negative for -b/2a to equal -10), getting -0.5x^2-10x+c. Plugging -10 in for x (since -10 is the middle it is the max), we get -50+100=50. Since the maximum needs to be 5, not 50, we subtract 45 from the answer to get it and therefore make c = -45, getting -0.5x^2-10x-45

5 0

3 years ago

Ax-c=b solve for x *show work

Makovka662 [10]

$ax-c=b\ \ \ |add\ c\ to\ both\ sides\\\\ax=b+c\ \ \ \ |divide\ both\ sides\ by\ a\\\\\boxed{x=\frac{b+c}{a}}$

4 0

2 years ago