Benzene lacks a polar O-H bond, but ethanol does. Benzene C6H6 with ethanol C2H6O.
Benzene fails the iodoform test, whereas ethanol does.
While ethanol burns with a non-luminous flame, benzene produces a sooty flame.
Iodoform testing shows that ethanol passes whereas benzene does not.
In contrast to benzene, which generates a sooty flame, ethanol burns with a non-luminous flame.
Water does not mix with benzene, but organic solvents do.
It is a colorless liquid with a pleasant scent.
Benzene has a high melting point and a moderate boiling point.
It burns with a sooty flame and is quite flammable.
A clear, colorless liquid, ethanol has a distinct flavor of burning with a nice aroma. It has high flammability. Ethanol combines easily with water and a variety of organic liquids and is used to dissolve other chemical compounds.
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Oxygen<span> is a </span>chemical element<span> having a symbol </span>O<span> and having an </span>atomic number<span> 8.
Oxygen is a pure substance , and it is not a mixture or solution, Niether it is a compound ... Instead , it forms chemical compounds by reacting with other elements.
So , according to above explanation ,
A. A pure substance , is the correct answer.</span>
Answers:
See below
Step-by-step explanation:
1. Most food energy
(a) Pringles
Heat from Pringles + heat absorbed by water = 0
m₁ΔH + m₂CΔT = 0
1.984ΔH + 100 × 4.184 × 18 = 0
1.984ΔH + 7530 = 0
ΔH = -7530/1.984 = -3800 J/g
(b) Cheetos
0.884ΔH + 418.4 × 13 = 0
ΔH = -5400/0.884 = -6200 J/g
Cheetos give you more food energy per gram.
(c) Snickers
Food energy = 215 Cal/28 g × 4184 J/1 Cal = 32 000 J/g
The food energy from Cheetos is much less than that from a Snickers bar
2. Experimental uncertainty
The experimental values are almost certainly too low.
Your burning food is heating up the air around it, so much of the heat of combustion is lost to the atmosphere.
3. Percent efficiency
Experimental food energy = 3800 J/g
Actual food energy = 150 Cal/28 g × 4184 J/1 Cal = 22 000 J/g
% Efficiency = Experimental value/Actual value × 100 %
= 3800/22 000 × 100 %
= 17 %
List of the metals that form only one type of ion (that is, metals whose charge is invariant from one compound to another) is below,
Here , we have to list the metals that form only one type of ion (that is, metals whose charge is invariant from one compound to another) and have to identify the group numbers of these metals.
- Hydrogen H+
- Lithium Li+
- Sodium Na+
- Potassium K+
- Rubidium Rb+
- Cesium Cs+
- Beryllium Be2+
- Magnesium Mg2+
- Calcium Ca2+
- Strontium Sr2+
- Barium Ba2+
- Aluminum Al3+
- Zinc Zn2+
- Scandium Sc3+
- Silver Ag+
Co is stable in both +2 and +3 oxidation state. So it can variable. Li only have +1 charge. So it is invariable from one compound to other.
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Answer:
most of them would move to another place to find a new home and A LOT of them would have died in the fir eor gotten injured and lost their homes
Explanation:
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