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3 years ago

Calculate the kelvin scale equivalent of 123 Celsius?

Chemistry

1 answer:

AlekseyPX3 years ago

5 0

Answer:

123 Celsius is equal to 396.15 Kelvin scale

Explanation:

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According to rounding rules for addition the sum of 27.1, 34.538, and 37.68 is

Katena32 [7]

The answer should be...99.318!

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3 years ago

Dalton incorporated the law of conservation of mass into his atomic theory by asserting that

Feliz [49]

Answer:

a. atoms are indivisible. ... atoms can not be destroyed in chemical reactions.

Explanation:

Hope this helped :D

7 0

3 years ago

Please help like please

klemol [59]

Answer:

It is the third one

Explanation:

"Both atoms achieve a more stable configuration."

4 0

3 years ago

Read 2 more answers

Calculate the volume of water which was liberated during the decomposition of hydrogen peroxide.

nikitadnepr [17]

The answer is :

The normal equation for the decomposition of hydrogen peroxide indicates that 2 vol. peroxide vapor should give rise to 2 vol. water vapor and 1 vol. oxygen.

What is hydrogen peroxide ?

Hydrogen peroxide is water (H2O) with an extra oxygen molecule (H2O2).
The extra oxygen molecule oxidizes, which is how peroxide gets its power says Dr. Beers.
This oxidation kills germs and bleaches color from porous surfaces like fabrics.
Hydrogen peroxide is found in biological systems including the human body.
Enzymes that use or decompose hydrogen peroxide are classified as peroxidases.

To learn more about Hydrogen peroxide visit: brainly.com/question/18709693?

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4 0

2 years ago

PLEASE HELP ASAP!

choli [55]

Answer:

$\large \boxed{\text{D. 710 g}}$

Explanation:

1. Calculate the molar mass of Na₂SO₄

$\begin{array}{ccc}\textbf{Atoms} &\textbf{M}_{\textbf{r}} & \textbf{Mass/u}\\\text{2Na} & 23 & 46\\\text{1S} & 32 & 32\\\text{4O}&16 & 64\\&\text{TOTAL =} & \mathbf{142}\\\end{array}$

The molar mass of Na₂SO₄ is 142 g/mol.

2. Calculate the moles of Na₂SO₄

$\text{Moles of Na$_{2}$SO}_{4} = \text{2.5 L solution} \times \dfrac{\text{2.0 mol Na$_{2}$SO}_{4}}{\text{1 L solution}} = \text{5.0 mol Na$_{2}$SO}_{4}$

3. Calculate the mass of Na₂SO₄

$\text{Mass of Na$_{2}$SO}_{4} = \text{5.0 mol Na$_{2}$SO}_{4} \times \dfrac{\text{142 g Na$_{2}$SO}_{4}}{\text{1 mol Na$_{2}$SO}_{4}} = \text{710 g Na$_{2}$SO}_{4}\\\\\text{You need } \large \boxed{\textbf{710 g}} \text{ of Na$_{2}$SO}_{4}$

6 0

3 years ago