Un globo de aire caliente tiene un volumen de 560 mL a la presión atmosférica normal y una temperatura del aire de 400 ºC. Cuand
o está en ascensión, y con el quemador de gas aumentamos la temperatura hasta los 700 ºC. ¿cuál será el nuevo volumen
1 answer:
Explanation:
charles law V1/T1 =V2/T2
560 x 673 =V2/973
376880 = V2/973
V2 = 376880 x 973 = 366704240mL
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Answer:
C-less than
Explanation:
Distance is total distance traveled (1000m here if you stop where you started).
Displacement is your final distance from where you started (0m if you stop where you started).
0m<1000m
Answer:
The answer to your question is: V2 = 1 l
Explanation:
Data
P1 = 200 kPa
P2 = 300 kPa
V1 = 1.5 l
V2 = ?
Formula
P1V1 = P2V2
V2 = (P1V1) / P2
V2 = (200 x 1.5) / 300
V2 = 1 l
Because it doesn't use energy it uses mechanical and kinetic
