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Georgia [21]
3 years ago
13

Un globo de aire caliente tiene un volumen de 560 mL a la presión atmosférica normal y una temperatura del aire de 400 ºC. Cuand

o está en ascensión, y con el quemador de gas aumentamos la temperatura hasta los 700 ºC. ¿cuál será el nuevo volumen
Physics
1 answer:
dalvyx [7]3 years ago
4 0

Explanation:

charles law V1/T1 =V2/T2

560 x 673 =V2/973

376880 = V2/973

V2 = 376880 x 973 = 366704240mL

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Answer:

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Explanation:

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\tan\theta=\dfrac{8}{3}

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