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3 years ago

6

A heavy box weighing 1000 newtons sits on the floor. You lift upward on the box with a force of 450 newtons, but the box does no

t move. What is the normal force on the box while you are lifting?

2 answers:

Svetllana [295]3 years ago

5 0

The answer for sure is 550

Ex: 1000 is the box
450 is your force
1000-450=550

Anvisha [2.4K]3 years ago

3 0

Answer:

i think its 550

Explanation:

1000-450 is 550

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We have that the values for F north, F east, F up are

$F_N=1.09090909*10^{-5}$
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From the Question we are told that

electric force $F_1 = 1.2 x 10^{-3} N(N)$

electric force , $F_2=5.7 x 10^{-4} N(E)$

electric force , $F_3=2.2 x 10^{-4} N (U)$

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charge on this ball two $q_2= -50 nC.$

Generally the equation for the F north is mathematically given as

$F_N=\frac{F_1}{q_1}\\\\F_N=\frac{ 1.2 * 10^{-3} )}{110}$

$F_N=1.09090909*10^{-5}$

For F East

$F_E=\frac{F_2}{q_1}\\\\F_E=\frac{5.7 x 10^-4 }{110}$

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For F UP

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That is;

ac = v²/r

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