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Basile [38]
3 years ago
6

A heavy box weighing 1000 newtons sits on the floor. You lift upward on the box with a force of 450 newtons, but the box does no

t move. What is the normal force on the box while you are lifting?
Physics
2 answers:
Svetllana [295]3 years ago
5 0
The answer for sure is 550

Ex: 1000 is the box
450 is your force
1000-450=550
Anvisha [2.4K]3 years ago
3 0

Answer:

i think its 550

Explanation:

1000-450 is 550

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What are the (time varying) amplitudes of the E and H fields if summer sunlight has an intensity of 1150 W/m2 in any Town?
Archy [21]

Explanation:

Given that,

Intensity = 1150 W/m²

(a). We need to calculate the magnetic field

Using formula of intensity

I=\dfrac{E^2}{2\mu_{0}c}

E=\sqrt{2\times I\mu_{0}c}

Put the value into the formula

E=\sqrt{2\times1150\times4\pi\times10^{-7}\times3\times10^{8}}

E=931.17\ N/C

Using formula of magnetic field

B = \dfrac{E}{c}

Put the value into the formula

B=\dfrac{931.17}{3\times10^{8}}

B=0.0000031039\ T

B=3.10\times10^{-6}\ T

(b). The relative strength of the gravitational and solar electromagnetic pressure forces of the sun on the earth

We need to calculate the gravitational force

Using gravitational force

F=\dfrac{Gm_{s}M_{e}}{r^2}

Put the value into the formula

F=\dfrac{6.67\times10^{-11}\times1.98\times10^{30}\times5.97\times10^{24}}{(1.496\times10^{11})^2}

F=3.522\times10^{22}\ N

We need to calculate the radiation force

Using formula of force

F_{R}=\dfrac{I}{c}\pi\timesR_{E}^{2}

Put the value into the formula

F_{R}=\dfrac{1150}{3\times10^{8}}\times\pi\times(6.378\times10^{6})^2

F_{R}=4.8\times10^{8}\ N

The gravitational and solar electromagnetic pressure forces of the sun on the earth

\dfrac{F_{G}}{F_{R}}=\dfrac{3.522\times10^{22}}{4.8\times10^{8}}

\dfrac{F_{G}}{F_{R}}=7.3375\times10^{13}

Hence, This is the required solution.

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3 years ago
The chances of being involved in an auto collision once a year are
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Very unlikely. This is not really a good question for Brainly.
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3 years ago
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Alexeev081 [22]
You might want to do a re-erp on this equation
5 0
3 years ago
Read 2 more answers
A pendulum Bob released from some initial height such that the speed of the bob at the bottom of the swing is 1.9m/s. What is th
Dmitriy789 [7]

Answer:

h = 18.4 cm

Explanation:

Given that,

The speed of the bob at the bottom of the swing is 1.9m/s.

We need to find the initial height of the bob. Let it is h.

We can find it using the conservation of energy i.e.

mgh=\dfrac{1}{2}mv^2

Where

v is speed of the bob

So,

h=\dfrac{v^2}{2g}\\\\h=\dfrac{(1.9)^2}{2\times 9.8}\\\\h= 0.184\ m

or

h = 18.4 cm

So, the initial height of the bob is 18.4 cm.

8 0
3 years ago
An alligator swims to the left with a constant velocity of 5 \,\dfrac{\text{m}}{\text s}5
dexar [7]

Answer:

The alligator will take t = 10 s to reach the final speed of 35 m/s

Explanation:

As we know that the initial speed of the alligator is 5 m/s

then it accelerate by given acceleration to reach the final speed of 35 m/s

so we will have

v_i = 5 m/s

v_f = 35 m/s

a = 3m/s^2

now we have

v_f = v_i + at

35 = 5 + 3 t

t = 10 s

5 0
3 years ago
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