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2 years ago

What best describes the speed of light waves in solids, liquids, and gases?

Physics

1 answer:

hammer [34]2 years ago

3 0

Answer:

Explanation:

Generally, the speed of light slows down when passing through a medium that is not a vacuum. This is not always the case, but I will be ignoring the rare/exotic exceptions. Light has a harder time traveling through solids and liquids than it does with gases.

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A converging-diverging nozzle has a throat area of 10 cm2 and an exit area of 28.96 cm2 . A normal shock stands in the exit when

Svetllana [295]

The tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.

The given parameters:

Throat area of the nozzle, $A^*$ = 10 cm² = 0.001 m²
The exit area of the nozzle, A = 28.96 cm² = 0.002896 m²
Air pressure at sea level = 101.325 kPa

The ratio of the areas of the converging-diverging nozzle is calculated as follows;

$= \frac{A}{A^*} \\\\= \frac{0.002896}{0.001} \\\\= 2.896$

From supersonic isentropic table, at $\frac{A}{A^*} = 2.896$ , we can determine the following;

$M_e = 2.6 \ kg/s\\\\\frac{P_o}{P_e} = 19.954$

The tank pressure is calculated as follows;

$\frac{P_o}{P_e} = 19.954 \\\\P_e = \frac{P_o}{19.954} \\\\P_e = \frac{101.325 \ kPa}{19.954} \\\\P_e = 5.08 \ kPa$

Thus, the tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.

Learn more about converging-diverging nozzle design here: brainly.com/question/13889483

8 0

2 years ago

Variations to the forehand stroke are not allowed. a. true b. false

timofeeve [1]

This is b. false

There are numerous ways of adjusting the forehand stroke and variations are allowed.

3 0

3 years ago

Read 2 more answers

Alan leaves Los Angeles at 8:00 A.M. to drive to San Francisco 400 mi away. He manages to travel at a steady 50 mph in spite of

Fudgin [204]

Answer:

a) Beth will reach before Alan

b)Beth has to wait 20 min for Alan to arrive

Explanation:

let 'd' be distance b/w Los Angeles and San Francisco i.e 400 mi

considering ,

Alan's speed $v_A$ =50mph

Beth's speed $v_B$ =60mph

->For Alan:

The time required $t_A$ = d/ $v_A$ = 400/50 => 8h

-> For beth:

The time required $t_B=\frac{d}{v_B} =\frac{400}{60} =>6\frac{2}{3} h$ => 6h 40m

Alan will reach at 8:00 a.m +8h = 4:00p.m.

Beth will reach at 9:00 a.m +6h 40m= 3:40p.m.

a) Beth will reach before Alan

b)Beth has to wait 20 min for Alan to arrive

3 0

3 years ago

You leave the doctor's office after your annual checkup and recall that you weighed 689 N in her office. You then get into an el

son4ous [18]

Answer: 0.455 m/s^2

Explanation:

f = ma = m x 9.8=689 (the mass is constant)

m = 78.3

now on the elevator

f = 721 = m x a

a= 10.26

the elevator is moving down because there is a increase in weight. the acceleration of elevator = 10.26-9.8 = 0.455

8 0

4 years ago

An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) whi

alexdok [17]

Actual displacement that he required to move

$d_1 = 5.4 km$ towards North

Displacement that he moved due to snow is

$d_2 = 8.1 km$ at 47 degree North of East

now in vector component form we can say

$d_1 = 5.4 \hat j$

$d_2 = 8.1 cos47 \hat i + 8.1 sin47 \hat j$

$d_2 = 5.52 \hat i + 5.92 \hat j$

now the displacement that is more required to reach the destination is given as

$d = d_1 - d_2$

$d = 5.4\hat j - (5.52 \hat i + 5.92\hat j)$

$d = -5.52 \hat i - 0.52 \hat j$

so the magnitude of the displacement is given as

$d = \sqrt{5.52^2 + 0.52^2}$

$d = 5.54 km$

its direction is given as

$\theta = tan^{-1}\frac{0.52}{5.52} = 5.38 degree$

so it is 5.54 km towards 5.38 degree North of West.

4 0

3 years ago