Answer:
Basically, fragrances reach other person through sense of smell. So, the strength of the fragrances depends a lot on its evaporation, which is strongly related to the boiling point. Esters with higher molecular weight do not have a strong fragrance because it has a higher boiling point.
<u>Answer:</u> The sample of Carbon-14 isotope will take 2377.9 years to decay it to 25 %
<u>Explanation:</u>
The equation used to calculate rate constant from given half life for first order kinetics:
![t_{1/2}=\frac{0.693}{k}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cfrac%7B0.693%7D%7Bk%7D)
where,
= half life of the reaction = 5730 years
Putting values in above equation, we get:
![k=\frac{0.693}{5730yrs}=1.21\times 10^{-4}yrs^{-1}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B0.693%7D%7B5730yrs%7D%3D1.21%5Ctimes%2010%5E%7B-4%7Dyrs%5E%7B-1%7D)
Rate law expression for first order kinetics is given by the equation:
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = ![1.21\times 10^{-4}yr^{-1}](https://tex.z-dn.net/?f=1.21%5Ctimes%2010%5E%7B-4%7Dyr%5E%7B-1%7D)
t = time taken for decay process = ? yr
= initial amount of the sample = 100 grams
[A] = amount left after decay process = (100 - 25) = 75 grams
Putting values in above equation, we get:
![1.21\times 10^{-4}=\frac{2.303}{t}\log\frac{100}{75}\\\\t=2377.9yrs](https://tex.z-dn.net/?f=1.21%5Ctimes%2010%5E%7B-4%7D%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B100%7D%7B75%7D%5C%5C%5C%5Ct%3D2377.9yrs)
Hence, the sample of Carbon-14 isotope will take 2377.9 years to decay it to 25 %
The crust
1. divergent (moves away from each other)
2. convergent (moves towards each other)
3. transform (slides past each other)
C=Carbon
O=Oxygen
Oxygen is a diatomic molecule, so the subscript two needs to be used after the O in the formula.
C+O2->CO2
Hope this helps!