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2 years ago

When Bob needs to send Alice a message with a digital signature, whose private key is used to encrypt the hash?

Physics

1 answer:

nadya68 [22]2 years ago

3 0

Answer: Bob's private key

Explanation:

Since Bob is sending Alice the message, it simply implies he must have encrypted it with his key that Alice can be able to use to decrypt the message.

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What would happen if I removed the battery from the circuit?

ira [324]

Answer:

The current would stop

Explanation:

Electric currents are interesting because they carry little to no momentum. As soon as you remove a power source, the whole current halts.

3 0

3 years ago

for an ideal monoatomic gas, the internal energy U os due to the kinetic energy and U=3/2RT per mole.show that cv=3/2R per mole

sladkih [1.3K]

Answer:

i. Cv =3R/2

ii. Cp = 5R/2

Explanation:

i. Cv = Molar heat capacity at constant volume

Since the internal energy of the ideal monoatomic gas is U = 3/2RT and Cv = dU/dT

Differentiating U with respect to T, we have

= d(3/2RT)/dT

= 3R/2

ii. Cp - Molar heat capacity at constant pressure

Cp = Cv + R

substituting Cv into the equation, we have

Cp = 3R/2 + R

taking L.C.M

Cp = (3R + 2R)/2

Cp = 5R/2

3 0

2 years ago

The wavelength of light is 5000 angstrom. Express it in nm and m.

Ierofanga [76]

Answer:

1 angstrom = 0.1nm

5000 angstrom = 5000/1 × 0.1nm

$1 \: angstrom = 1 \times {10}^{ - 10} m$

5000 angstrom = 5000 × 1 × 10^-10

Hope this helps you

7 0

3 years ago

As you take your leisurely tour through the solar system, you come across a 1.45 kg rock that was ejected from a collision of as

nikklg [1K]

Answer:

$1.3310\times 10^8 m/s$ is the rock's speed.

Explanation:

Momentum is defined as motion possessed by the moving body's mass. Mathematically it a product of mas and velocity of the body.

$Momentum(P)=Mass(m)\times velocity(v)$

Given : Mass of rock = m = 1.45 kg

Velocity of the rock = v

Momentum of the rock = P = $1.93\times 10^8 kg m/s$

$1.93\times 10^8 kg m/s=1.45 kg\times v$

$v=\frac{1.93\times 10^8 kg m/s}{1.45 kg}=1.33\times 10^8 m/s$

$1.3310\times 10^8 m/s$ is the rock's speed.

6 0

3 years ago

What is the pendulum length whose period is 2.0s ?

Mashutka [201]

$Formula\ for\ period:\\\ T=2 \pi \sqrt{\frac{L}{g}}\\\ g-gravity=9,8 \frac{m}{s^2} ,\ L-pendulum \ length \\\\ \frac{T}{2 \pi } = \sqrt{ \frac{L}{g} }|square\\\\ \frac{T^2}{2 \pi } = \frac{L}{g} \\\\\ \frac{T^2}{2 \pi }*g=L\\\\ L= \frac{2^2}{2*3,14 }*9,8= \frac{39,2}{6,28} =6,24m$ $T=2 \pi \sqrt{\frac{L}{g}} \\
 \frac{T}{2 \pi } = \sqrt{ \frac{L}{g} }|square\\
 \frac{T^2}{2 \pi } = \frac{L}{g} \\
 \frac{T^2}{2 \pi }*g=L\\
L= \frac{2^2}{2*3,14 }*9,8= \frac{39,2}{6,28} =6,24m
$

7 0

3 years ago