Answer:
R = 73.25 m
Explanation:
We have,
Initial speed of the ball is 27 m/s
It is projected at an angle of 40 degrees
The maximum range of the ball is given by :

Plugging all the values we get :

So, the maximum range of the ball is 73.25 m
Natrual selection is where animalz better adapt to their enviroment
Answer:

Explanation:
Here by ideal gas equation we can say

now we know that pressure is kept constant here
so we will have

since we know that number of moles and pressure is constant here
so we have

now we know that initial temperature is 17.8 degree C
and finally volume is doubled
So we have

so final temperature will be


Answer:
sliding , static , rolling
Explanation:
HOPE IT WILL HELP YOU
U = 0, initial upward speed
a = 29.4 m/s², acceleration up to 3.98 s
a = -9.8 m/s², acceleration after 3.98s
Let h₁ = the height at time t, for t ≤ 3.98 s
Let h₂ = the height at time t > 3.98 s
Motion for t ≤ 3.98 s:
h₁ = (1/2)*(29.4 m/s²)*(3.98 s)² = 232.854 m
Calculate the upward velocity at t = 3.98 s
v₁ = (29.4 m/s²)*(3.98 s) = 117.012 m/s
Motion for t > 3.98 s
At maximum height, the upward velocity is zero.
Calculate the extra distance traveled before the velocity is zero.
(117.012 m/s)² + 2*(-9.8 m/s²)*(h₂ m) = 0
h₂ = 698.562 m
The total height is
h₁ + h₂ = 232.854 + 698.562 = 931.416 m
Answer: 931.4 m (nearest tenth)