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Kobotan [32]
3 years ago
7

I have 20 electrons and 4 energy levels. *

Chemistry
1 answer:
katen-ka-za [31]3 years ago
3 0

Answer:

Ca, also known as Calcium

Explanation:

Get a periodic table. In the top left hand corner are of each element's box is a number. This is how many protons are present. Protons are equal to electrons, therefore calcium has 20 electrons. It is in group 2A period 4 if that helps.

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Which clue can be used to identify a chemical reaction as a decomposition reaction?
inn [45]

Answer:

plzz mark brainliast:

Explanation:

clue: The reaction has a single reactant.

8 0
4 years ago
Read 2 more answers
How many moles are in 3.90 x1030 atoms of Zn?
zaharov [31]
Explanation:
The problem basically wants you to find a way to convert between the number of atoms present in the sample and the number of moles they are equivalent to.
To convert between atoms and moles we use something called Avogadro's constant, which basically acts as the definition of a mole.
More specifically, in order to have one mole of an element you need
6.022 x 10^23 atoms of that element. You can thus use this number as a conversion factor to take you from atoms to moles or vice versa.
In your case, you will have


3.90 x 10^ 26 atoms Zn x 1 mole Zn ( Avogrado’s constant) / 6.022 x 10^23 atoms Zn

= 6.5 x 10^8 is the answer
7 0
3 years ago
I need Help Asap<br> PLlLlzzzz
ohaa [14]
I believe it would be agricultural because it is the most filled in on the graph.
3 0
3 years ago
If 23.17 g of beryllium (Be) reacts with water at standard temperature and pressure,
emmainna [20.7K]

Volume of H2 produced = 57.6576 L

<h3>Further explanation</h3>

Given

23.17 g Be

Required

Volume of H2

Solution

Reaction

Be(s)+H2O(g)→BeO(s)+H2(g)

mol Be :

= 23.17 g : 9 g/mol

= 2.574

From the equation, mol H2 : mol Be = 1 : 1, so mol H2 = 2.574

Volume H2(assumed at STP, 1 mol=22.4 L) :

= 2.574 x 22.4 L

= 57.6576 L

5 0
3 years ago
How many moles of oxygen are in 25.45 g of caco3?
emmainna [20.7K]
From the periodic table:
mass of oxygen = 16 grams
mass of calcium = 40 grams
mass of carbon = 12 grams
mass of CaCO3 = 40 + 12 + 3(16) = 100 grams
Therefore, each 100 grams of CaCO3 contains 3 moles of oxygen
To know the number of oxygen moles in 25.45 grams, we will simply do cross multiplication as follows:
number of oxygen moles = (25.45 x 3) / 100 = 0.7636
3 0
3 years ago
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