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Arlecino [84]
2 years ago
6

What does the letter "E" represents when in a chemical equation

Chemistry
1 answer:
Amiraneli [1.4K]2 years ago
7 0

Answer:

1. Equality

<u><em>Hope this helps :)</em></u>

<em><u>Pls brainliest...</u></em>

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. Name the solute and solvent in the following: a. 14-karat gold b. corn syrup c. carbonated, or sparkling, water
Elena L [17]

Answer:

a) gold-solvent

silver+ copper-solute

b) solvent- water

solute- sugar

c) solute- CO2

solvent- H2O

8 0
2 years ago
What do dipole-dipole forces do?
g100num [7]
An ion-dipole force is a type of intermolecular force in which forces of attraction or repulsion occur between neighboring ions, molecules or atoms.
3 0
3 years ago
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How can I differentiate between Ionic compounds, molecular compounds, and acids given only the formula? I need to be able to fin
VikaD [51]
You can differentiate between ionic, covalent and molecular compounds by the fact that ionic compounds contain elements that include both a metal and a nonmetal. Molecular compounds contain both non metals covalently bonded to each other. While acids most often on their chemical formula start with the element of Hydrogen - H.

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hydrochloric acid - HCl.
7 0
3 years ago
The change in internal energy for the combustion of 1.0 mol of octane at a pressure of 1.0 atm is -5084.1 kj . f the change in e
TEA [102]

<u>Given:</u>

Change in internal energy = ΔU = -5084.1 kJ

Change in enthalpy = ΔH = -5074.3 kJ

<u>To determine:</u>

The work done, W

<u>Explanation:</u>

Based on the first law of thermodynamics,

ΔH = ΔU + PΔV

the work done by a gas is given as:

W = -PΔV

Therefore:

ΔH = ΔU - W

W = ΔU-ΔH = -5084.1 -(-5074.3) = -9.8 kJ

Ans: Work done is -9.8 kJ


6 0
3 years ago
What is the new concentration of a solution of CaSO3 if 10.0 mL of a 2.0 M CaSO3 solution is diluted to 100 ml?
kifflom [539]

Answer: The new concentration of a solution of CaSO_{3} is 0.2 M 10.0 mL of a 2.0 M CaSO_{3} solution is diluted to 100 mL.

Explanation:

Given: V_{1} = 10.0 mL,      M_{1} = 2.0 M

V_{2} = 100 mL,           M_{2} = ?

Formula used to calculate the new concentration is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\10.0 mL \times 2.0 M = M_{2} \times 100 mL\\M_{2} = 0.2 M

Thus, we can conclude that the new concentration of a solution of CaSO_{3} is 0.2 M 10.0 mL of a 2.0 M CaSO_{3} solution is diluted to 100 mL.

5 0
2 years ago
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