The equation is y=mx+c
C=8
M=-1
![\nabla f(x,y)=\left\langle\dfrac{\partial f}{\partial x},\dfrac{\partial f}{\partial y}\right\rangle=\left\langle\dfrac{2x}{x^2+y^2},\dfrac{2y}{x^2+y^2}\right\rangle](https://tex.z-dn.net/?f=%5Cnabla%20f%28x%2Cy%29%3D%5Cleft%5Clangle%5Cdfrac%7B%5Cpartial%20f%7D%7B%5Cpartial%20x%7D%2C%5Cdfrac%7B%5Cpartial%20f%7D%7B%5Cpartial%20y%7D%5Cright%5Crangle%3D%5Cleft%5Clangle%5Cdfrac%7B2x%7D%7Bx%5E2%2By%5E2%7D%2C%5Cdfrac%7B2y%7D%7Bx%5E2%2By%5E2%7D%5Cright%5Crangle)
You didn't provide the "given point", but I assume you're capable of plugging it in.
Answer: it is p
Step-by-step explanation:
Answer:
140m
Step-by-step explanation:
3/4 = .75
x/.7 = 150/.75
multiply both sides by .7
x = 150/.75 * .7
x = 140m
Answer:
Let "x" be the number of people who can go to the amusement park.
So we have: 19 + 14x ≤ 180. This inequality basically means that the parking cost plus the cost of the tickets for every person cannot cost more than 180 dollars.
Solving this inequality, we get:
19 + 14x ≤ 180
14x ≤ 161
x ≤ 11.5
Obviously, we know that we can't have "half" a person, so the most people who can come to the amusement park would be 11 people, and the answer would be: x ≤ 11
Hope this helps!