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3 years ago

This is due tomorrow... :How can you tell the mass was conserved in a chemical reaction?

Chemistry

1 answer:

kipiarov [429]3 years ago

3 0

Answer:

Matter cannot be created or destroyed in chemical reactions. This is the law of conservation of mass. In every chemical reaction, the same mass of matter must end up in the products as started in the reactants. Balanced chemical equations show that mass is conserved in chemical reactions.

Explanation:

hope this help :)

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When 10 g of diethyl ether is converted to vapor at its boiling point, about how much heat is absorbed? (c4h10o, δhvap = 15.7 kj

vagabundo [1.1K]

Answer:

ΔH= 3KJ

Explanation:

The total heat absorbed is the total energy in the process, and that is in form of entalpy.

ΔH = q + ΔHvap, where q is the heat necessary for elevate the temperature of dietil ether. Suppose the initial temperature is room temperature (25ºC=298 K), then

q= 10g x2.261 J/gK x(310 K - 298K)= 271.32 J= 0.3 kJ

Then

ΔHvap = 10g C4H10O x (1 mol C4H10O/74.12 g C4H10O) x( 15.7 KJ/ 1 mol C4H10O) = 2.12 KJ

ΔH= 2.5KJ ≈ 3KJ

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4 years ago

A student is studying the boiling points of six different liquids and finds results with consistently higher boiling points than

almond37 [142]

Answer:

Large molecules tend to have greater boiling points because the London dispersion forces are stronger within.

Explanation:

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2 years ago

PLEASE HELP I AM FAILING

Gwar [14]

Answer:

160.3 g S

Explanation: there you go

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3 years ago

6. what is the metric system prefix for the quantity 0.000 001? a) centi- b) deci- c) kilo- d) micro-

Sergeeva-Olga [200]

The metric system prefix for the above quantity would be D. Micro. Which is 10^-6.

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3 years ago

Read 2 more answers

Solve this word problem:

valina [46]

Answer:

The new acceleration becomes twice the pervious acceleration.

Explanation:

Given that,

Mass of the rock, m = 3 kg

Force, F = 1 N

We know that the force acting on an object is given by :

F = ma

a is acceleration of the rock

Put m = 3 kg and F = 1N,

$a=\dfrac{F}{m}\\\\a=\dfrac{1}{3}\ m/s^2$

If the force is doubled, F' = 2 N

So,

F'=ma'

$a'=\dfrac{F'}{m}\\\\a'=\dfrac{2\times 1}{3}\\\\a'=\dfrac{2}{3}\\\\a'=2\times \dfrac{1}{3}\\\\a'=2a$

So, the new acceleration becomes twice the initial acceleration.

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3 years ago