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igor_vitrenko [27]
3 years ago
7

WORTH 50 POINTS!!!! PLZ HELP ME!! ASAP!!

Physics
1 answer:
ratelena [41]3 years ago
6 0
The volume of the rock has a deeper density than the cylinder.
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An engine takes in 2400 J of heat, and rejects 1880 J of heat into the air. What is the efficiency of the engine? (No Unit)
Galina-37 [17]

Answer:

.2166 repeating or 21.66% repeating

Explanation:

In attached image

8 0
3 years ago
What process is used in this example? You have learned that all living things use energy. Your dog is a living thing. She must u
oksano4ka [1.4K]
Option B.) Deductive Reasoning
8 0
3 years ago
If someone ways 600 newtons and the shoes have an area of 300cm squared, what pressure does he exert on the ground?
lukranit [14]
Pressure = Force / Area

Put your data in front of yourself.

Force = 600 Newtons
Area = 300 cm^2

Firstly you need to convert the area into m^2 and you do this by diving 300 with 10000.

Now you use the formula:-
Pressure = 600/ 0.03
Which comes out to be 20,000 Pa.

Hope this helps!
4 0
3 years ago
Which of the following represents a chemical property of hydrogen gas? A) It is gaseous at room temperature. B) It is less dense
ehidna [41]

Answer:

C) It reacts explosively with oxygen.

Explanation:

Physical properties are usually those that can be observed using our senses such as color, luster, freezing point, boiling point, melting point, density, hardness and odor.

What are the Chemical Properties of Hydrogen? They are the characteristics that determine how it will react with other substances or change from one substance to another.

3 0
3 years ago
4. A trolley of mass 2kg rests next to a trolley of mass 3 kg on a flat
nydimaria [60]

Answer:

a. The total momentum of the trolleys which are at rest before the separation is zero

b. The total momentum of the trolleys after separation is zero

c. The momentum of the 2 kg trolley after separation is 12 kg·m/s

d. The momentum of the 3 kg trolley is -12 kg·m/s

e. The velocity of the 3 kg trolley = -4 m/s

Explanation:

a. The total momentum of the trolleys which are at rest before the separation is zero

b. By the principle of the conservation of linear momentum, the total momentum of the trolleys after separation = The total momentum of the trolleys before separation = 0

c. The momentum of the 2 kg trolley after separation = Mass × Velocity = 2 kg × 6 m/s = 12 kg·m/s

d. Given that the total momentum of the trolleys after separation is zero, the momentum of the 3 kg trolley is equal and opposite to the momentum of the 2 kg trolley = -12 kg·m/s

e. The momentum of the 3 kg trolley = Mass of the 3 kg Trolley × Velocity of the 3 kg trolley

∴ The momentum of the 3 kg trolley = 3 kg × Velocity of the 3 kg trolley = -12 kg·m/s

The velocity of the 3 kg trolley = -12 kg·m/s/(3 kg) = -4 m/s

3 0
3 years ago
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