Answer:
See answers below
Explanation:
a.
F = mg,
F = (1500 kg)(9.8 m/s²) = 14,700 N
b.
2500 N - 175 N = 2325 N
Answer: The correct answer is- The plant with the smooth seeds is homozygous for the dominant trait.
According to the Mendelian genetics, dominant trait is the one that expresses itself and masks the expression of the recessive trait. Dominant is depicted with capital letter and recessive with small letter.
Let us consider 'S' depicts the allele for smooth seed and 's' for the wrinkled seeds. There can be two genotypes for smooth seeds that is 'Ss' and 'SS' whereas only one genotype is possible for wrinkled ( 'ss') seeds.
As per the question, there is no chance of the offspring born with wrinkled seeds. This is only possible when the parental plant with smooth seeds is homozygous for the dominant trait ( like SS) . Therefore, only smooth trait will be visible in the offsprings ( with genotype Ss) of the parental plants and there will be no chance of wrinkled seeds (ss) in the offsprings.
The resistance in this circuit is 39.8 ohms.
Explanation:
Any circuit having resistor, battery and ammeter connected in series will obey the ohm's law in basic case. So according to the Ohm's law, the current flowing in the circuit through the ammeter will be equal to the voltage shown in the voltmeter or battery and resistor is the proportionality constant. So with this law
V = IR
So, Resistance R = V/I
As the voltage is given as 23.90 V and the current is given as 0.6 A, then resistance is
R = 23.90/0.6 = 39.8 ohms.
So, the resistance in this circuit is 39.8 ohms.
Answer:
b
Explanation:
because the metalloids are the thing in the middle
Answer:
it's B. circuit a and b are series circuit while c is parallel
