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fenix001 [56]
4 years ago
12

For each of the cases listed below, decide whether or not the motion described is an example of acceleration: (T/F)

Physics
1 answer:
scoundrel [369]4 years ago
8 0

Answer:

1. True

2. True

3. False

4. False

5. True

6. False

Explanation:

Acceleration: It refers to the change in velocity/speed of an object with respect to time. When the speed increases with time we call it acceleration and when its decreases it is called as deceleration.  Let us analyze each instance individually:

1. When roller coaster starts to roll down the track its speed will increase with time. That means it is accelerating.

2. When the ball reaches at the peak of its trajectory, it comes to a stop for a fraction of a second that means it decelerates.

3. Since the velocity remains constant there is no acceleration.

4. Since the speed is no changing with time, there is no acceleration.

5. Since the moving plane comes to a stop, it is a case of deceleration.

6. Since the truck is moving at a constant speed so the acceleration is zero.

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Answer:

Va-Vb=168KV

Explanation:

From the question we are told that

Two points charge of 4\mu C and 2\mu C

Generally we find the  Va and Vb individually to find there difference

Given a rectangle with two equal sides each,Assume lengths for bot sides

Length L=0.3

Breath B=0.4

Diagonal D=\sqrt{0.3^2+0.4^2} =0.5

at  opposite sides

Mathematically Va can represented as

Va =k(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )

Va =9*10^9(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )

Va =9*10^9(0.00001333333-0.000004} )

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Mathematically Vb is  represented as

Va =k(\frac{-4*10^_-_6}{0.3} +\frac{2*10^_-_6}{0.5} )

Va =9*10^9(\frac{-4*10^_-_6}{0.3} +\frac{+2*10^_-_6}{0.5} )

Va =9*10^9(-0.00001333333+0.000004} )

Va =-84000V

Va =-84KV

Therefore

Va-Vb=84-(-84)\\Va-Vb=84+84\\Va-Vb=168KV

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