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Zielflug [23.3K]
3 years ago
7

This type of stretch keeps your heart rate elevated and muscles warm.

Physics
2 answers:
Illusion [34]3 years ago
4 0

Answer:

dynamic and sometimes ballistic

natta225 [31]3 years ago
3 0

Answer:

dynamic

Explanation:

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WILL GIVE BRAINLIEST!!!
vovikov84 [41]

Answer:

D.

boulder-sized rocks that come from the asteroid belt

3 0
3 years ago
An increase in resistance causes the flow of electric current to
Zolol [24]

An increase in voltage causes the flow of electric current to INCREASE. An increase in resistance causes the flow of electric current to DECREASE.

100% right

6 0
3 years ago
Read 2 more answers
The recoil of a shotgun can be significant. Suppose a 3.6-kg shotgun is held tightly by an arm and shoulder with a combined mass
devlian [24]

Answer:

The velocity of the recoil is v=1.001 \frac{m}{s}

Explanation:

Kinetic Energy

m_{bullet}*v_{bullet}=m_{gun}*v_{recoil}\\m_{gun}= 15.0kg+3.6kg

The mass of th gun is the both mass the shotgun and the arm shoulder combination

m_{bullet}=0.049kg\\v_{bullet}=380\frac{m}{s} \\m_{bullet}*v_{bullet}=m_{gun}*v_{recoil}\\0.049kg*380\frac{m}{s}=(15.kg+3.6kg)* v_{recoil}\\v_{recoil}=-\frac{18.62 kg \frac{m}{s} }{18.6 kg}\\ v_{recoil}=-1.0010 \frac{m}{s}

The velocity is negative because is in opposite direction of the bullet

6 0
3 years ago
Read 2 more answers
The electric field of a sinusoidal electromagnetic wave obeys the equation E = (360V/m) sin[ (6.00×1015rad/s)t + (1.96×107rad/m)
malfutka [58]

Answer:

Option D is correct.

Explanation:

Bmax = Emax / c

The general form for electromagnetic wave equation is

E = jEmax ×cos(kx-wt)

We were given

(360V/m) sin[ (6.00×1015rad/s)t + (1.96×107rad/m)x ].

So from the equation above

Emax = 360V/m

Bmax = 360/(3×10⁸) = 1.2 ×10‐⁶ T.

5 0
3 years ago
Read 2 more answers
You buy a plastic dart gun, and being a clever physics student you decide to do a quick calculation to find its maximum horizont
Scilla [17]

Answer:

R_{max} = 51.84 m

Explanation:

When we shoot the dart upwards the time taken by the dart to go straight up and again come back is given as

t = 4.6 s

here we can say

\Delta y = 0 = v_i t + \frac{1}{2}at^2

0 = v_i t - \frac{1}{2}(9.8)t^2

put t = 4.6 s then we have

v_i = 22.54 s

Now in order to find the maximum range we can say

R = \frac{v^2 sin2\theta}{g}

so in order to have maximum range we can say

\theta = 45 degree

R_{max} = \frac{v^2}{g}

R_{max} = \frac{22.54^2}{9.8}

R_{max} = 51.84 m

5 0
3 years ago
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