1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mandarinka [93]
2 years ago
12

A solution is prepared by dissolving 40.0 g of sucrose, in 250 g of water at 25°C. What is the vapor pressure of the solution if

the vapor pressure of water at 25°C is 23.76 mm Hg?
Chemistry
2 answers:
Lapatulllka [165]2 years ago
3 0

Answer:

  • <em>The vapor pressure of the solution at 25°C is </em><u><em>23.6 mmHg</em></u>

Explanation:

<u>1) Data:</u>

  • Mass of solute, sucroese, m₁ = 40.0 g
  • Mass of solvent, water, m₂ = 250. g
  • Vapor pressure of solution, p = ?
  • Vapor pressure of pure water, p⁰ = 23.76 mm Hg

<u>2) Principles and formulae:</u>

  • Raoult's law states that the vapor pressure of a solution is equal to the mole fraction of the solvent times the vapor pressure of the pure liquid.

        p = X p⁰

       

<u>3) Solution:</u>

a) <u>Mole fraction of the solvent (water)</u>

  • X = number of moles of solvent / number of moles of solution

  • number of moles of solvent, n₁ = mass in grams / molar mass

         n₁ = 250. g / 18.015 g/mol = 13.88 moles

  • number of moles of solute, n₂ = mass in grams / molar mass

        n₂ = 40.0 g / 342,3 g/mol = 0.12 moles

  • total number of moles, n₁ + n₂ = 13.88 moles + 0.12 moles = 14.0 moles

  • moles fraction of water, X = 13.88 moles / 14.0 moles = 0.99

b) <u>Vapor pressure of the solution</u>:

  • p = p⁰ X = 23.76 mmHg × 0.99 = 23.56 mm Hg

Rounding to three significant figures: 23.6 mm Hg.

seropon [69]2 years ago
3 0

The vapor pressure of the solution : P = <u>23.57 mmHg</u>

<h3>Further explanation </h3>

Solution properties are the properties of a solution that don't depend on the type of solute but only on the concentration of the solute.

Solution properties of electrolyte solutions differ from non-electrolyte solutions because electrolyte solutions contain a greater number of particles because electrolytes break down into ions. So the Solution properties of electrolytes is greater than non-electrolytes.

The term is used in the Solution properties

  • 1. molal

that is, the number of moles of solute in 1 kg of solvent

\large {\boxed {\bold {m = mole. \frac {1000} {mass \: of \: solvent (in \: grams)}}}

  • 2. mole fraction

the ratio of the number of moles of solute to the mole of solution

\large {\boxed {\bold {Xa = \frac {na} {na + nb}}}

  • 3. Vapor pressure

Vapor pressure depends on the mole fraction of the components in the solution

P = Xs. P °

P = vapor pressure solution

P ° = pure vapor pressure

Xs = mole fraction solvent

ΔP = P ° - P where

ΔP = change in vapor pressure

Molar mass of sucrose-C₁₂H₂₂O₁₁: 342  g/mole

mole sucrose = 40.0 g : 342 = 0.116

Molar mass of water = 18

mole water = 250 g : 18 = 13.88

Xs = mole fraction solvent = mole of water : total mole

Xs = 13.88 : (13.88 + 0.116)

Xs = 0.992

P° = 23.76 mm Hg

so that

P = 0.992. 23.76

P = 23.57 mmHg

<h3>Learn more   </h3>

colligative properties  

brainly.com/question/8567736  

Raoult's law  

brainly.com/question/10165688  

The vapor pressure of benzene  

brainly.com/question/11102916  

The freezing point of a solution  

brainly.com/question/8564755  

brainly.com/question/4593922  

brainly.com/question/1196173  

 

Keywords: vapor pressure, sucrose, water

You might be interested in
What is the name of H3PO4?
asambeis [7]
Phosphoric Acid - The last answer choice
3 0
3 years ago
What happens to the matter in the body of an animal after it dies
sladkih [1.3K]
The matter will be consumed by other living organisms and the blood will settle to the bottom of the body
4 0
3 years ago
1. Do you think that the lightbulb and the Moon spheres are "to scale" compared to the real
Tems11 [23]

Answer:

Yes

Explanation: Had a question like this and I said yes and got it right

3 0
2 years ago
Calculate the change in enthalpy for the following reaction, using the bond enthalpy data provided below. (Note: you may round t
aliina [53]

Answer:

-514 kJ/mol

Explanation:

The bond enthalpy which is also known as bond energy can be defined as the amount of energy needed to split one mole of the stated bond. The change in enthalpy of a given reaction can be estimated by subtracting the sum of the bond energies of the reactants from the sum of the bond energies of the products.

For the given chemical reaction, the change in enthalpy of the reaction is:

ΔH_{rxn} = [2(409) + 4(388) + 3(496) - 4(630) - 4(463)] kJ/mol = 818 + 1552 + 1488 - 2520 - 1852 = -514 kJ/mol

3 0
3 years ago
True/False: Animal embryos look similar early in development because all animals share a common ancestor.
user100 [1]
You should go on yahoo answers and ask it! Someone will get back to you
8 0
2 years ago
Read 2 more answers
Other questions:
  • When Dimitri Mendelev first developed the periodic table, one of the most important features that he introduced was starting a n
    8·2 answers
  • What is volcanoes be my friend
    7·2 answers
  • How many moles of each substance are needed to prepare the following solutions?
    12·1 answer
  • Oxidation-reduction is often the most confusing and abstract part of chemistry for first-time chemistry students. Is it really w
    7·1 answer
  • Which is the best definition of non polar covalent bond?
    5·2 answers
  • Iron forms rust, expressed as Fe2O3.
    6·1 answer
  • When you combine 50.0 mL of 0.100 M AgNO3 with 50.0 mL of 0.100 M HCl in a coffee-cup calorimeter, the temperature changes from
    15·1 answer
  • The pitcher’s mound in baseball is 85 m from the plate how fast is the pitch
    10·1 answer
  • Gizmo Warm-up Like an unpopped kernel in the microwave, a radioactive atom can change at any time. Radioactive atoms change by e
    7·1 answer
  • Which of the following is an ether?<br> A)<br> B)<br> C)<br> D)
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!