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3 years ago

This type of pollution will decay naturally

Chemistry

1 answer:

butalik [34]3 years ago

3 0

Withdrawal is the answer to your question.

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A sample of a hydrocarbon contains 20.75 g C and 4.25 g H. Its molar mass is 58.04 g/mol. What is its empirical formula C2H5 CH2

Xelga [282]

It is c2h5 if you our doing it on edunitey thats all i can say

6 0

3 years ago

Read 2 more answers

Choose which of the following are organic. (check all that apply) *

Charra [1.4K]

Answer:

The answer is A, B and E

Explanation:

A - carbohydrates

B - Lipids

C- COH

E - Proteins

all except O and NaOH

7 0

3 years ago

What is the molarity of the solution formed by mixing 0.20mol of sodium hydroxide with enough water to make 150 ml of solution?

bixtya [17]

Molarity is defined as the number of moles of solute in 1 L of solution
number of NaOH moles present - 0.20 mol
volume of solution - 150 mL
since molarity is taken as number moles of solute in 1000 mL
if 150 mL contains - 0.20 mol
then 1000 mL should contain - 0.20 / 150 x 1000 = 1.33 mol
therefore molarity is 1.33 M

3 0

3 years ago

Convert 15.2 moles of K to atoms of K.

choli [55]

Answer:

$\boxed {\boxed {\sf 9.15*10^{24} \ atoms \ K}}$

Explanation:

To convert atoms to moles, Avogadro's Number must be used: 6.022*10²³.

This tells us the amount of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case it is the atoms of potassium. We can create a ratio.

$\frac {6.022*10^{23} \ atoms \ K }{ 1 \ mol \ K }$

Multiply by the given number of moles: 15.2

$15.2 \ mol \ K *\frac {6.022*10^{23} \ atoms \ K }{ 1 \ mol \ K }$

The moles of potassium cancel.

$15.2 *\frac {6.022*10^{23} \ atoms \ K }{ 1 }$

The denominator of 1 can be ignored.

$15.2 * {6.022*10^{23} \ atoms \ K }{$

Multiply.

$9.15344*10^{24} \ atoms \ K$

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated that is the hundredth place. The 3 in the thousandth place tells us to leave 5.

$9.15*10^{24} \ atoms \ K$

In 15.2 moles of potassium, there are <u>9.15*10²⁴ atoms of potassium.</u>

3 0

3 years ago

When 1.5 grams of magnesium burns, how many grams of magnesium oxide will be formed?

SashulF [63]

The balanced chemical reaction for this would be written as:

2Mg + O2 = 2MgO

We use this reaction and the amount of the reactant given to calculate for the amount of magnesium oxide that is produced. We do as follows:

1.5 g Mg (1 mol / 24.31 g) ( 2 mol MgO / 2 mol Mg ) (40.30 g /1 mol ) = 2.49 g MgO produced

6 0

3 years ago